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شائع علم المثلثات >

170=(90^2)/(16)sin(x)cos(x)

الحلّ

170 = \frac{9 0 ^{2}}{16} sin (x) cos (x)

الحلّ

x = \frac{0.73637 \dots}{2} + πn, x = \frac{π}{2} - \frac{0.73637 \dots}{2} + πn

+1

درجات

x = 21.09552 \dots^{\circ} + 18 0^{\circ} n, x = 68.90447 \dots^{\circ} + 18 0^{\circ} n

خطوات الحلّ

170 = \frac{9 0 ^{2}}{16} sin (x) cos (x)

بدّل الأطراف

\frac{9 0 ^{2}}{16} sin (x) cos (x) = 170

Rewrite using trig identities

\frac{9 0 ^{2}}{16} sin (x) cos (x)

2 sin (x) cos (x) = sin (2 x)

:فعّل متطابقة الزاوية المضاعفة

sin (x) cos (x) = \frac{sin ( 2 x )}{2}

= \frac{sin ( 2 x )}{2} \cdot \frac{9 0 ^{2}}{16}

\frac{sin ( 2 x )}{2} \cdot \frac{9 0 ^{2}}{16} = 170

\frac{sin ( 2 x )}{2} \cdot \frac{9 0 ^{2}}{16}

بسّط:

\frac{2025 sin ( 2 x )}{8}

\frac{sin ( 2 x )}{2} \cdot \frac{9 0 ^{2}}{16}

\frac{9 0 ^{2}}{16} = \frac{3 ^{4} \cdot 5 ^{2}}{2 ^{2}}

\frac{9 0 ^{2}}{16}

9 0^{2}

حلل إلى عوامل:

3^{4} \cdot 2^{2} \cdot 5^{2}

90 = 3^{2} \cdot 2 \cdot 5

حلّل إلى عوامل

= (3^{2} \cdot 2 \cdot 5)^{2}

(ab)^{c} = a^{c} b^{c}

:فعّل قانون القوى

= 2^{2} \cdot 5^{2} (3^{2})^{2}

(3^{2})^{2}

بسّط:

3^{4}

(3^{2})^{2}

(a^{b})^{c} = a^{b c}

:فعّل قانون القوى

= 3^{2 \cdot 2}

2 \cdot 2 = 4 :

اضرب الأعداد

= 3^{4}

= 3^{4} \cdot 2^{2} \cdot 5^{2}

16

حلل إلى عوامل:

2^{4}

16 = 2^{4}

حلّل إلى عوامل

= \frac{3 ^{4} \cdot 2 ^{2} \cdot 5 ^{2}}{2 ^{4}}

\frac{2 ^{2} \cdot 3 ^{4} \cdot 5 ^{2}}{2 ^{4}}

اختزل:

\frac{3 ^{4} \cdot 5 ^{2}}{2 ^{2}}

\frac{2 ^{2} \cdot 3 ^{4} \cdot 5 ^{2}}{2 ^{4}}

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

:فعّل قانون القوى

\frac{2 ^{2}}{2 ^{4}} = \frac{1}{2 ^{4 - 2}}

= \frac{3 ^{4} \cdot 5 ^{2}}{2 ^{4 - 2}}

4 - 2 = 2 :

اطرح الأعداد

= \frac{3 ^{4} \cdot 5 ^{2}}{2 ^{2}}

= \frac{3 ^{4} \cdot 5 ^{2}}{2 ^{2}}

= \frac{3 ^{4} \cdot 5 ^{2}}{2 ^{2}} \cdot \frac{sin ( 2 x )}{2}

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

:اضرب كسور

= \frac{sin ( 2 x ) \cdot 3 ^{4} \cdot 5 ^{2}}{2 \cdot 2 ^{2}}

2 \cdot 2^{2} = 2^{3}

2 \cdot 2^{2}

a^{b} \cdot a^{c} = a^{b + c}

:فعّل قانون القوى

2 \cdot 2^{2} = 2^{1 + 2}

= 2^{1 + 2}

1 + 2 = 3 :

اجمع الأعداد

= 2^{3}

= \frac{3 ^{4} \cdot 5 ^{2} sin ( 2 x )}{2 ^{3}}

sin (2 x) \cdot 3^{4} \cdot 5^{2} = 2025 sin (2 x)

sin (2 x) \cdot 3^{4} \cdot 5^{2}

3^{4} = 81

= 5^{2} \cdot 81 sin (2 x)

5^{2} = 25

= 81 \cdot 25 sin (2 x)

81 \cdot 25 = 2025 :

اضرب الأعداد

= 2025 sin (2 x)

= \frac{2025 sin ( 2 x )}{2 ^{3}}

2^{3} = 8

= \frac{2025 sin ( 2 x )}{8}

\frac{2025 sin ( 2 x )}{8} = 170

8

اضرب الطرفين بـ

\frac{2025 sin ( 2 x )}{8} = 170

8

اضرب الطرفين بـ

\frac{8 \cdot 2025 sin ( 2 x )}{8} = 170 \cdot 8

بسّط

2025 sin (2 x) = 1360

2025 sin (2 x) = 1360

2025

اقسم الطرفين على

2025 sin (2 x) = 1360

2025

اقسم الطرفين على

\frac{2025 sin ( 2 x )}{2025} = \frac{1360}{2025}

بسّط

sin (2 x) = \frac{272}{405}

sin (2 x) = \frac{272}{405}

Apply trig inverse properties

sin (2 x) = \frac{272}{405}

sin (2 x) = \frac{272}{405} :

حلول عامّة لـ

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

2 x = arcsin (\frac{272}{405}) + 2 πn, 2 x = π - arcsin (\frac{272}{405}) + 2 πn

2 x = arcsin (\frac{272}{405}) + 2 πn, 2 x = π - arcsin (\frac{272}{405}) + 2 πn

2 x = arcsin (\frac{272}{405}) + 2 πn

حلّ:

x = \frac{arcsin ( \frac{272}{405} )}{2} + πn

2 x = arcsin (\frac{272}{405}) + 2 πn

2

اقسم الطرفين على

2 x = arcsin (\frac{272}{405}) + 2 πn

2

اقسم الطرفين على

\frac{2 x}{2} = \frac{arcsin ( \frac{272}{405} )}{2} + \frac{2 πn}{2}

بسّط

x = \frac{arcsin ( \frac{272}{405} )}{2} + πn

x = \frac{arcsin ( \frac{272}{405} )}{2} + πn

2 x = π - arcsin (\frac{272}{405}) + 2 πn

حلّ:

x = \frac{π}{2} - \frac{arcsin ( \frac{272}{405} )}{2} + πn

2 x = π - arcsin (\frac{272}{405}) + 2 πn

2

اقسم الطرفين على

2 x = π - arcsin (\frac{272}{405}) + 2 πn

2

اقسم الطرفين على

\frac{2 x}{2} = \frac{π}{2} - \frac{arcsin ( \frac{272}{405} )}{2} + \frac{2 πn}{2}

بسّط

x = \frac{π}{2} - \frac{arcsin ( \frac{272}{405} )}{2} + πn

x = \frac{π}{2} - \frac{arcsin ( \frac{272}{405} )}{2} + πn

x = \frac{arcsin ( \frac{272}{405} )}{2} + πn, x = \frac{π}{2} - \frac{arcsin ( \frac{272}{405} )}{2} + πn

أظهر الحلّ بالتمثيل العشريّ

x = \frac{0.73637 \dots}{2} + πn, x = \frac{π}{2} - \frac{0.73637 \dots}{2} + πn

رسم

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