cos(θ)=(sqrt(11))/5

Lösung

cos (θ) = \frac{11}{5}

θ = 0.84554 \dots + 2 πn, θ = 2 π - 0.84554 \dots + 2 πn

Grad

θ = 48.44605 \dots^{\circ} + 36 0^{\circ} n, θ = 311.55394 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{11}{5}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{11}{5}

Allgemeine Lösung für

cos (θ) = \frac{11}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{11}{5}) + 2 πn, θ = 2 π - arccos (\frac{11}{5}) + 2 πn

θ = arccos (\frac{11}{5}) + 2 πn, θ = 2 π - arccos (\frac{11}{5}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.84554 \dots + 2 πn, θ = 2 π - 0.84554 \dots + 2 πn

4 cos^{2} (x) tan (x) - tan (x) = 0

2 cos (\frac{π}{4} - 3 x) = 2

3 sec^{2} (x) = sec (x)

tan^{2} (x) - 1 = sec^{2} (x)

cos (3 x) = \frac{π}{6}