cos(θ)= 12/20

Lösung

cos (θ) = \frac{12}{20}

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

Grad

θ = 53.13010 \dots^{\circ} + 36 0^{\circ} n, θ = 306.86989 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{12}{20}

Streiche die gemeinsamen Faktoren:

4

cos (θ) = \frac{3}{5}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{3}{5}

Allgemeine Lösung für

cos (θ) = \frac{3}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

cos (θ) = \frac{12}{15}

arctan (x) = 45

tan^{2} (x) + cot^{2} (x) - 2 = 0

(1 + 2 cos (2 x))^{2} = 0

tan (2 x) = 0.6