sin(t)= 1/5

解答

sin (t) = \frac{1}{5}

t = 0.20135 \dots + 2 πn, t = π - 0.20135 \dots + 2 πn

度数

t = 11.53695 \dots^{\circ} + 36 0^{\circ} n, t = 168.46304 \dots^{\circ} + 36 0^{\circ} n

求解步骤

sin (t) = \frac{1}{5}

使用反三角函数性质

sin (t) = \frac{1}{5}

sin (t) = \frac{1}{5}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

t = arcsin (\frac{1}{5}) + 2 πn, t = π - arcsin (\frac{1}{5}) + 2 πn

t = arcsin (\frac{1}{5}) + 2 πn, t = π - arcsin (\frac{1}{5}) + 2 πn

以小数形式表示解

t = 0.20135 \dots + 2 πn, t = π - 0.20135 \dots + 2 πn

sin (θ) = \frac{- 1}{2}

3 (tan (x) + sin^{2} (x)) - 4 = 4 tan (x) - 3 cos^{2} (x)

1.33 \cdot sin (5 6^{\circ}) = 1 \cdot sin (x)

cosh (x) = sinh (x)

csc (x) tan (x) = \frac{2 3}{3}