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受欢迎的三角函数 >

sin(arcsin(1/2)+arccos(1/2))

解答

sin (arcsin (\frac{1}{2}) + arccos (\frac{1}{2}))

解答

1

求解步骤

sin (arcsin (\frac{1}{2}) + arccos (\frac{1}{2}))

使用三角恒等式改写:

sin (arcsin (\frac{1}{2})) cos (arccos (\frac{1}{2})) + cos (arcsin (\frac{1}{2})) sin (arccos (\frac{1}{2}))

sin (arcsin (\frac{1}{2}) + arccos (\frac{1}{2}))

使用角和恒等式:

sin (s + t) = sin (s) cos (t) + cos (s) sin (t)

= sin (arcsin (\frac{1}{2})) cos (arccos (\frac{1}{2})) + cos (arcsin (\frac{1}{2})) sin (arccos (\frac{1}{2}))

= sin (arcsin (\frac{1}{2})) cos (arccos (\frac{1}{2})) + cos (arcsin (\frac{1}{2})) sin (arccos (\frac{1}{2}))

使用三角恒等式改写:

sin (arcsin (\frac{1}{2})) = \frac{1}{2}

利用以下特性:

sin (arcsin (x)) = x

= \frac{1}{2}

使用三角恒等式改写:

cos (arccos (\frac{1}{2})) = \frac{1}{2}

利用以下特性:

cos (arccos (x)) = x

= \frac{1}{2}

使用三角恒等式改写:

cos (arcsin (\frac{1}{2})) = \frac{3}{2}

cos (arcsin (\frac{1}{2}))

使用三角恒等式改写:

cos (arcsin (\frac{1}{2})) = 1 - (\frac{1}{2})^{2}

利用以下特性:

cos (arcsin (x)) = 1 - x^{2}

= 1 - (\frac{1}{2})^{2}

= 1 - (\frac{1}{2})^{2}

化简

= \frac{3}{2}

使用三角恒等式改写:

sin (arccos (\frac{1}{2})) = \frac{3}{2}

sin (arccos (\frac{1}{2}))

使用三角恒等式改写:

sin (arccos (\frac{1}{2})) = 1 - (\frac{1}{2})^{2}

利用以下特性:

sin (arccos (x)) = 1 - x^{2}

= 1 - (\frac{1}{2})^{2}

= 1 - (\frac{1}{2})^{2}

化简

= \frac{3}{2}

= \frac{1}{2} \cdot \frac{1}{2} + \frac{3}{2} \cdot \frac{3}{2}

化简

\frac{1}{2} \cdot \frac{1}{2} + \frac{3}{2} \cdot \frac{3}{2} : 1

\frac{1}{2} \cdot \frac{1}{2} + \frac{3}{2} \cdot \frac{3}{2}

\frac{1}{2} \cdot \frac{1}{2} = \frac{1}{4}

\frac{1}{2} \cdot \frac{1}{2}

分式相乘:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{2 \cdot 2}

数字相乘:

1 \cdot 1 = 1

= \frac{1}{2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{1}{4}

\frac{3}{2} \cdot \frac{3}{2} = \frac{3}{4}

\frac{3}{2} \cdot \frac{3}{2}

分式相乘:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 3}{2 \cdot 2}

33 = 3

33

使用根式运算法则:

a a = a

33 = 3

= 3

= \frac{3}{2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{3}{4}

= \frac{1}{4} + \frac{3}{4}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 3}{4}

数字相加:

1 + 3 = 4

= \frac{4}{4}

使用法则

\frac{a}{a} = 1

= 1

= 1

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