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受欢迎的三角函数 >

2sin(30)+3cos(60)-3tan(45)

解答

2 sin (3 0^{\circ}) + 3 cos (6 0^{\circ}) - 3 tan (4 5^{\circ})

解答

- \frac{1}{2}

+1

十进制

- 0.5

求解步骤

2 sin (3 0^{\circ}) + 3 cos (6 0^{\circ}) - 3 tan (4 5^{\circ})

使用以下普通恒等式:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

使用以下普通恒等式:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

周期表（周期为

36 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

使用以下普通恒等式:

tan (4 5^{\circ}) = 1

tan (4 5^{\circ})

tan (x)

周期表（周期为

18 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 1

= 2 \cdot \frac{1}{2} + 3 \cdot \frac{1}{2} - 3 \cdot 1

化简

2 \cdot \frac{1}{2} + 3 \cdot \frac{1}{2} - 3 \cdot 1 : - \frac{1}{2}

2 \cdot \frac{1}{2} + 3 \cdot \frac{1}{2} - 3 \cdot 1

同类项相加:

2 \cdot \frac{1}{2} + 3 \cdot \frac{1}{2} = 5 \cdot \frac{1}{2}

= 5 \cdot \frac{1}{2} - 3 \cdot 1

5 \cdot \frac{1}{2} = \frac{5}{2}

5 \cdot \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 5}{2}

数字相乘:

1 \cdot 5 = 5

= \frac{5}{2}

3 \cdot 1 = 3

3 \cdot 1

数字相乘:

3 \cdot 1 = 3

= 3

= \frac{5}{2} - 3

将项转换为分式:

3 = \frac{3 \cdot 2}{2}

= - \frac{3 \cdot 2}{2} + \frac{5}{2}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 \cdot 2 + 5}{2}

- 3 \cdot 2 + 5 = - 1

- 3 \cdot 2 + 5

数字相乘:

3 \cdot 2 = 6

= - 6 + 5

数字相加/相减:

- 6 + 5 = - 1

= - 1

= \frac{- 1}{2}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

= - \frac{1}{2}

流行的例子

cos(arcsin(4/5)+arccos(3/5))

cos (arcsin (\frac{4}{5}) + arccos (\frac{3}{5}))

cos (2) (90)

3 tan (4 5^{\circ})

tan (0.53)

((3pi)/2)cos(0)-sec(2pi)

(\frac{3 π}{2}) cos (0) - sec (2 π)