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人気のある三角関数 >

証明する (sin(x)tan(x))/(cos(x)+1)=sec(x)-1

解

証明する

\frac{sin ( x ) tan ( x )}{cos ( x ) + 1} = sec (x) - 1

解

真

解答ステップ

\frac{sin ( x ) tan ( x )}{cos ( x ) + 1} = sec (x) - 1

左側を操作する

\frac{sin ( x ) tan ( x )}{cos ( x ) + 1}

サイン, コサインで表わす

\frac{sin ( x ) tan ( x )}{1 + cos ( x )}

基本的な三角関数の公式を使用する:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{sin ( x ) \frac{s i n ( x )}{c o s ( x )}}{1 + cos ( x )}

簡素化

\frac{sin ( x ) \frac{s i n ( x )}{c o s ( x )}}{1 + cos ( x )} : \frac{sin ^{2} ( x )}{cos ( x ) ( 1 + cos ( x ) )}

\frac{sin ( x ) \frac{s i n ( x )}{c o s ( x )}}{1 + cos ( x )}

乗じる

sin (x) \frac{sin ( x )}{cos ( x )} : \frac{sin ^{2} ( x )}{cos ( x )}

sin (x) \frac{sin ( x )}{cos ( x )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( x ) sin ( x )}{cos ( x )}

sin (x) sin (x) = sin^{2} (x)

sin (x) sin (x)

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

sin (x) sin (x) = sin^{1 + 1} (x)

= sin^{1 + 1} (x)

数を足す:

1 + 1 = 2

= sin^{2} (x)

= \frac{sin ^{2} ( x )}{cos ( x )}

= \frac{\frac{s i n ^{2} ( x )}{c o s ( x )}}{1 + cos ( x )}

分数の規則を適用する:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{sin ^{2} ( x )}{cos ( x ) ( 1 + cos ( x ) )}

= \frac{sin ^{2} ( x )}{cos ( x ) ( 1 + cos ( x ) )}

= \frac{sin ^{2} ( x )}{( 1 + cos ( x ) ) cos ( x )}

三角関数の公式を使用して書き換える

\frac{sin ^{2} ( x )}{( 1 + cos ( x ) ) cos ( x )}

ピタゴラスの公式を使用する:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= \frac{1 - cos ^{2} ( x )}{( 1 + cos ( x ) ) cos ( x )}

簡素化

\frac{1 - cos ^{2} ( x )}{( 1 + cos ( x ) ) cos ( x )} : - \frac{cos ( x ) - 1}{cos ( x )}

\frac{1 - cos ^{2} ( x )}{( 1 + cos ( x ) ) cos ( x )}

因数

1 - cos^{2} (x) : - (cos (x) + 1) (cos (x) - 1)

1 - cos^{2} (x)

共通項をくくり出す

- 1

= - (cos^{2} (x) - 1)

因数

cos^{2} (x) - 1 : (cos (x) + 1) (cos (x) - 1)

cos^{2} (x) - 1

1

を書き換え

1^{2}

= cos^{2} (x) - 1^{2}

2乗の差の公式を適用する:

x^{2} - y^{2} = (x + y) (x - y)

cos^{2} (x) - 1^{2} = (cos (x) + 1) (cos (x) - 1)

= (cos (x) + 1) (cos (x) - 1)

= - (cos (x) + 1) (cos (x) - 1)

= - \frac{( cos ( x ) + 1 ) ( cos ( x ) - 1 )}{( 1 + cos ( x ) ) cos ( x )}

共通因数を約分する:

cos (x) + 1

= - \frac{cos ( x ) - 1}{cos ( x )}

= - \frac{cos ( x ) - 1}{cos ( x )}

= - \frac{cos ( x ) - 1}{cos ( x )}

拡張

- \frac{- 1 + cos ( x )}{cos ( x )} : \frac{1}{cos ( x )} - 1

- \frac{- 1 + cos ( x )}{cos ( x )}

分数の規則を適用する:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 1 + cos ( x )}{cos ( x )} = - (- \frac{1}{cos ( x )}) - (\frac{cos ( x )}{cos ( x )})

= - (- \frac{1}{cos ( x )}) - (\frac{cos ( x )}{cos ( x )})

括弧を削除する:

(a) = a, - (- a) = a

= \frac{1}{cos ( x )} - \frac{cos ( x )}{cos ( x )}

規則を適用

\frac{a}{a} = 1

= \frac{1}{cos ( x )} - 1

= - 1 + \frac{1}{cos ( x )}

簡素化

- 1 + \frac{1}{cos ( x )} : \frac{- cos ( x ) + 1}{cos ( x )}

- 1 + \frac{1}{cos ( x )}

元を分数に変換する:

1 = \frac{1 cos ( x )}{cos ( x )}

= - \frac{1 \cdot cos ( x )}{cos ( x )} + \frac{1}{cos ( x )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot cos ( x ) + 1}{cos ( x )}

乗算:

1 \cdot cos (x) = cos (x)

= \frac{- cos ( x ) + 1}{cos ( x )}

= \frac{1 - cos ( x )}{cos ( x )}

三角関数の公式を使用して書き換える

基本的な三角関数の公式を使用する:

cos (x) = \frac{1}{sec ( x )}

\frac{1 - \frac{1}{s e c ( x )}}{\frac{1}{s e c ( x )}}

簡素化

\frac{1 - \frac{1}{s e c ( x )}}{\frac{1}{s e c ( x )}}

分数の規則を適用する:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{( 1 - \frac{1}{s e c ( x )} ) sec ( x )}{1}

結合

1 - \frac{1}{sec ( x )} : \frac{sec ( x ) - 1}{sec ( x )}

1 - \frac{1}{sec ( x )}

元を分数に変換する:

1 = \frac{1 sec ( x )}{sec ( x )}

= \frac{1 \cdot sec ( x )}{sec ( x )} - \frac{1}{sec ( x )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot sec ( x ) - 1}{sec ( x )}

乗算:

1 \cdot sec (x) = sec (x)

= \frac{sec ( x ) - 1}{sec ( x )}

= \frac{\frac{s e c ( x ) - 1}{s e c ( x )} sec ( x )}{1}

分数の規則を適用する:

\frac{a}{1} = a

= \frac{sec ( x ) - 1}{sec ( x )} sec (x)

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( sec ( x ) - 1 ) sec ( x )}{sec ( x )}

共通因数を約分する:

sec (x)

= sec (x) - 1

sec (x) - 1

sec (x) - 1

両辺を同じ形式にできることを証明した

\Rightarrow 真

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