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人気のある 三角関数 >

証明する 2sec(2x)=tan(pi/4+x)+tan(pi/4-x)

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解

証明する 2sec(2x)=tan(4π​+x)+tan(4π​−x)

解

真
解答ステップ
2sec(2x)=tan(4π​+x)+tan(4π​−x)
右側を操作するtan(4π​+x)+tan(4π​−x)
三角関数の公式を使用して書き換える
tan(4π​+x)
基本的な三角関数の公式を使用する: tan(x)=cos(x)sin(x)​=cos(4π​+x)sin(4π​+x)​
角の和の公式を使用する: sin(s+t)=sin(s)cos(t)+cos(s)sin(t)=cos(4π​+x)sin(4π​)cos(x)+cos(4π​)sin(x)​
角の和の公式を使用する: cos(s+t)=cos(s)cos(t)−sin(s)sin(t)=cos(4π​)cos(x)−sin(4π​)sin(x)sin(4π​)cos(x)+cos(4π​)sin(x)​
簡素化 cos(4π​)cos(x)−sin(4π​)sin(x)sin(4π​)cos(x)+cos(4π​)sin(x)​:cos(x)−sin(x)cos(x)+sin(x)​
cos(4π​)cos(x)−sin(4π​)sin(x)sin(4π​)cos(x)+cos(4π​)sin(x)​
sin(4π​)cos(x)+cos(4π​)sin(x)=22​​cos(x)+22​​sin(x)
sin(4π​)cos(x)+cos(4π​)sin(x)
簡素化 sin(4π​):22​​
sin(4π​)
次の自明恒等式を使用する:sin(4π​)=22​​
sin(x)2πn 循環を含む周期性テーブル:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
=22​​
=22​​cos(x)+cos(4π​)sin(x)
簡素化 cos(4π​):22​​
cos(4π​)
次の自明恒等式を使用する:cos(4π​)=22​​
cos(x)2πn 循環を含む周期性テーブル:
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
=22​​
=22​​cos(x)+22​​sin(x)
=cos(4π​)cos(x)−sin(4π​)sin(x)22​​cos(x)+22​​sin(x)​
cos(4π​)cos(x)−sin(4π​)sin(x)=22​​cos(x)−22​​sin(x)
cos(4π​)cos(x)−sin(4π​)sin(x)
簡素化 cos(4π​):22​​
cos(4π​)
次の自明恒等式を使用する:cos(4π​)=22​​
cos(x)2πn 循環を含む周期性テーブル:
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
=22​​
=22​​cos(x)−sin(4π​)sin(x)
簡素化 sin(4π​):22​​
sin(4π​)
次の自明恒等式を使用する:sin(4π​)=22​​
sin(x)2πn 循環を含む周期性テーブル:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
=22​​
=22​​cos(x)−22​​sin(x)
=22​​cos(x)−22​​sin(x)22​​cos(x)+22​​sin(x)​
乗じる 22​​cos(x):22​cos(x)​
22​​cos(x)
分数を乗じる: a⋅cb​=ca⋅b​=22​cos(x)​
=22​cos(x)​−22​​sin(x)22​​cos(x)+22​​sin(x)​
乗じる 22​​sin(x):22​sin(x)​
22​​sin(x)
分数を乗じる: a⋅cb​=ca⋅b​=22​sin(x)​
=22​cos(x)​−22​sin(x)​22​​cos(x)+22​​sin(x)​
乗じる 22​​cos(x):22​cos(x)​
22​​cos(x)
分数を乗じる: a⋅cb​=ca⋅b​=22​cos(x)​
=22​cos(x)​−22​sin(x)​22​cos(x)​+22​​sin(x)​
乗じる 22​​sin(x):22​sin(x)​
22​​sin(x)
分数を乗じる: a⋅cb​=ca⋅b​=22​sin(x)​
=22​cos(x)​−22​sin(x)​22​cos(x)​+22​sin(x)​​
分数を組み合わせる 22​cos(x)​−22​sin(x)​:22​cos(x)−2​sin(x)​
規則を適用 ca​±cb​=ca±b​=22​cos(x)−2​sin(x)​
=22​cos(x)−2​sin(x)​22​cos(x)​+22​sin(x)​​
分数を組み合わせる 22​cos(x)​+22​sin(x)​:22​cos(x)+2​sin(x)​
規則を適用 ca​±cb​=ca±b​=22​cos(x)+2​sin(x)​
=22​cos(x)−2​sin(x)​22​cos(x)+2​sin(x)​​
分数を割る: dc​ba​​=b⋅ca⋅d​=2(2​cos(x)−2​sin(x))(2​cos(x)+2​sin(x))⋅2​
共通因数を約分する:2=2​cos(x)−2​sin(x)2​cos(x)+2​sin(x)​
共通項をくくり出す 2​=2​cos(x)−2​sin(x)2​(cos(x)+sin(x))​
共通項をくくり出す 2​=2​(cos(x)−sin(x))2​(cos(x)+sin(x))​
共通因数を約分する:2​=cos(x)−sin(x)cos(x)+sin(x)​
=cos(x)−sin(x)cos(x)+sin(x)​
=cos(x)−sin(x)cos(x)+sin(x)​+tan(4π​−x)
三角関数の公式を使用して書き換える
tan(4π​−x)
基本的な三角関数の公式を使用する: tan(x)=cos(x)sin(x)​=cos(4π​−x)sin(4π​−x)​
角の差の公式を使用する: sin(s−t)=sin(s)cos(t)−cos(s)sin(t)=cos(4π​−x)sin(4π​)cos(x)−cos(4π​)sin(x)​
角の差の公式を使用する: cos(s−t)=cos(s)cos(t)+sin(s)sin(t)=cos(4π​)cos(x)+sin(4π​)sin(x)sin(4π​)cos(x)−cos(4π​)sin(x)​
簡素化 cos(4π​)cos(x)+sin(4π​)sin(x)sin(4π​)cos(x)−cos(4π​)sin(x)​:cos(x)+sin(x)cos(x)−sin(x)​
cos(4π​)cos(x)+sin(4π​)sin(x)sin(4π​)cos(x)−cos(4π​)sin(x)​
sin(4π​)cos(x)−cos(4π​)sin(x)=22​​cos(x)−22​​sin(x)
sin(4π​)cos(x)−cos(4π​)sin(x)
簡素化 sin(4π​):22​​
sin(4π​)
次の自明恒等式を使用する:sin(4π​)=22​​
sin(x)2πn 循環を含む周期性テーブル:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
=22​​
=22​​cos(x)−cos(4π​)sin(x)
簡素化 cos(4π​):22​​
cos(4π​)
次の自明恒等式を使用する:cos(4π​)=22​​
cos(x)2πn 循環を含む周期性テーブル:
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
=22​​
=22​​cos(x)−22​​sin(x)
=cos(4π​)cos(x)+sin(4π​)sin(x)22​​cos(x)−22​​sin(x)​
cos(4π​)cos(x)+sin(4π​)sin(x)=22​​cos(x)+22​​sin(x)
cos(4π​)cos(x)+sin(4π​)sin(x)
簡素化 cos(4π​):22​​
cos(4π​)
次の自明恒等式を使用する:cos(4π​)=22​​
cos(x)2πn 循環を含む周期性テーブル:
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
=22​​
=22​​cos(x)+sin(4π​)sin(x)
簡素化 sin(4π​):22​​
sin(4π​)
次の自明恒等式を使用する:sin(4π​)=22​​
sin(x)2πn 循環を含む周期性テーブル:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
=22​​
=22​​cos(x)+22​​sin(x)
=22​​cos(x)+22​​sin(x)22​​cos(x)−22​​sin(x)​
乗じる 22​​cos(x):22​cos(x)​
22​​cos(x)
分数を乗じる: a⋅cb​=ca⋅b​=22​cos(x)​
=22​cos(x)​+22​​sin(x)22​​cos(x)−22​​sin(x)​
乗じる 22​​sin(x):22​sin(x)​
22​​sin(x)
分数を乗じる: a⋅cb​=ca⋅b​=22​sin(x)​
=22​cos(x)​+22​sin(x)​22​​cos(x)−22​​sin(x)​
乗じる 22​​cos(x):22​cos(x)​
22​​cos(x)
分数を乗じる: a⋅cb​=ca⋅b​=22​cos(x)​
=22​cos(x)​+22​sin(x)​22​cos(x)​−22​​sin(x)​
乗じる 22​​sin(x):22​sin(x)​
22​​sin(x)
分数を乗じる: a⋅cb​=ca⋅b​=22​sin(x)​
=22​cos(x)​+22​sin(x)​22​cos(x)​−22​sin(x)​​
分数を組み合わせる 22​cos(x)​+22​sin(x)​:22​cos(x)+2​sin(x)​
規則を適用 ca​±cb​=ca±b​=22​cos(x)+2​sin(x)​
=22​cos(x)+2​sin(x)​22​cos(x)​−22​sin(x)​​
分数を組み合わせる 22​cos(x)​−22​sin(x)​:22​cos(x)−2​sin(x)​
規則を適用 ca​±cb​=ca±b​=22​cos(x)−2​sin(x)​
=22​cos(x)+2​sin(x)​22​cos(x)−2​sin(x)​​
分数を割る: dc​ba​​=b⋅ca⋅d​=2(2​cos(x)+2​sin(x))(2​cos(x)−2​sin(x))⋅2​
共通因数を約分する:2=2​cos(x)+2​sin(x)2​cos(x)−2​sin(x)​
共通項をくくり出す 2​=2​cos(x)+2​sin(x)2​(cos(x)−sin(x))​
共通項をくくり出す 2​=2​(cos(x)+sin(x))2​(cos(x)−sin(x))​
共通因数を約分する:2​=cos(x)+sin(x)cos(x)−sin(x)​
=cos(x)+sin(x)cos(x)−sin(x)​
=cos(x)−sin(x)cos(x)+sin(x)​+cos(x)+sin(x)cos(x)−sin(x)​
簡素化 cos(x)−sin(x)cos(x)+sin(x)​+cos(x)+sin(x)cos(x)−sin(x)​:(cos(x)−sin(x))(cos(x)+sin(x))2cos2(x)+2sin2(x)​
cos(x)−sin(x)cos(x)+sin(x)​+cos(x)+sin(x)cos(x)−sin(x)​
以下の最小公倍数: cos(x)−sin(x),cos(x)+sin(x):(cos(x)−sin(x))(cos(x)+sin(x))
cos(x)−sin(x),cos(x)+sin(x)
最小公倍数 (LCM)
cos(x)−sin(x) または以下のいずれかに現れる因数で構成された式を計算する: cos(x)+sin(x)=(cos(x)−sin(x))(cos(x)+sin(x))
LCMに基づいて分数を調整する
該当する分母を乗じてLCMに変えるために
必要な量で各分子を乗じる (cos(x)−sin(x))(cos(x)+sin(x))
cos(x)−sin(x)cos(x)+sin(x)​の場合:分母と分子に以下を乗じる: cos(x)+sin(x)cos(x)−sin(x)cos(x)+sin(x)​=(cos(x)−sin(x))(cos(x)+sin(x))(cos(x)+sin(x))(cos(x)+sin(x))​=(cos(x)−sin(x))(cos(x)+sin(x))(cos(x)+sin(x))2​
cos(x)+sin(x)cos(x)−sin(x)​の場合:分母と分子に以下を乗じる: cos(x)−sin(x)cos(x)+sin(x)cos(x)−sin(x)​=(cos(x)+sin(x))(cos(x)−sin(x))(cos(x)−sin(x))(cos(x)−sin(x))​=(cos(x)−sin(x))(cos(x)+sin(x))(cos(x)−sin(x))2​
=(cos(x)−sin(x))(cos(x)+sin(x))(cos(x)+sin(x))2​+(cos(x)−sin(x))(cos(x)+sin(x))(cos(x)−sin(x))2​
分母が等しいので, 分数を組み合わせる: ca​±cb​=ca±b​=(cos(x)−sin(x))(cos(x)+sin(x))(cos(x)+sin(x))2+(cos(x)−sin(x))2​
拡張 (cos(x)+sin(x))2+(cos(x)−sin(x))2:2cos2(x)+2sin2(x)
(cos(x)+sin(x))2+(cos(x)−sin(x))2
(cos(x)+sin(x))2:cos2(x)+2cos(x)sin(x)+sin2(x)
完全平方式を適用する: (a+b)2=a2+2ab+b2a=cos(x),b=sin(x)
=cos2(x)+2cos(x)sin(x)+sin2(x)
=cos2(x)+2cos(x)sin(x)+sin2(x)+(cos(x)−sin(x))2
(cos(x)−sin(x))2:cos2(x)−2cos(x)sin(x)+sin2(x)
完全平方式を適用する: (a−b)2=a2−2ab+b2a=cos(x),b=sin(x)
=cos2(x)−2cos(x)sin(x)+sin2(x)
=cos2(x)+2cos(x)sin(x)+sin2(x)+cos2(x)−2cos(x)sin(x)+sin2(x)
簡素化 cos2(x)+2cos(x)sin(x)+sin2(x)+cos2(x)−2cos(x)sin(x)+sin2(x):2cos2(x)+2sin2(x)
cos2(x)+2cos(x)sin(x)+sin2(x)+cos2(x)−2cos(x)sin(x)+sin2(x)
類似した元を足す:2cos(x)sin(x)−2cos(x)sin(x)=0=cos2(x)+sin2(x)+cos2(x)+sin2(x)
類似した元を足す:cos2(x)+cos2(x)=2cos2(x)=2cos2(x)+sin2(x)+sin2(x)
類似した元を足す:sin2(x)+sin2(x)=2sin2(x)=2cos2(x)+2sin2(x)
=2cos2(x)+2sin2(x)
=(cos(x)−sin(x))(cos(x)+sin(x))2cos2(x)+2sin2(x)​
=(cos(x)−sin(x))(cos(x)+sin(x))2cos2(x)+2sin2(x)​
因数 (cos(x)+sin(x))(cos(x)−sin(x))2cos2(x)+2sin2(x)​:(cos(x)+sin(x))(cos(x)−sin(x))2(cos2(x)+sin2(x))​
(cos(x)+sin(x))(cos(x)−sin(x))2cos2(x)+2sin2(x)​
因数 2cos2(x)+2sin2(x):2(cos2(x)+sin2(x))
2cos2(x)+2sin2(x)
共通項をくくり出す 2=2(cos2(x)+sin2(x))
=(cos(x)+sin(x))(cos(x)−sin(x))2(cos2(x)+sin2(x))​
=(cos(x)+sin(x))(cos(x)−sin(x))(cos2(x)+sin2(x))⋅2​
三角関数の公式を使用して書き換える
(cos(x)+sin(x))(cos(x)−sin(x))(cos2(x)+sin2(x))⋅2​
ピタゴラスの公式を使用する: cos2(x)+sin2(x)=1=(cos(x)+sin(x))(cos(x)−sin(x))1⋅2​
簡素化=(cos(x)+sin(x))(cos(x)−sin(x))2​
拡張 (cos(x)+sin(x))(cos(x)−sin(x)):cos2(x)−sin2(x)
(cos(x)+sin(x))(cos(x)−sin(x))
2乗の差の公式を適用する:(a+b)(a−b)=a2−b2a=cos(x),b=sin(x)=cos2(x)−sin2(x)
=cos2(x)−sin2(x)2​
2倍角の公式を使用: cos2(x)−sin2(x)=cos(2x)=cos(2x)2​
=cos(2x)2​
三角関数の公式を使用して書き換える
基本的な三角関数の公式を使用する: cos(x)=sec(x)1​sec(2x)1​2​
簡素化
sec(2x)1​2​
分数の規則を適用する: cb​a​=ba⋅c​=12sec(2x)​
規則を適用 1a​=a=2sec(2x)
2sec(2x)
2sec(2x)
両辺を同じ形式にできることを証明した⇒真

人気の例

証明する sin(x)-csc(x)=-(cos(x))(cot(x))provesin(x)−csc(x)=−(cos(x))(cot(x))証明する cos(θ)=sin(3θ+62)provecos(θ)=sin(3θ+62)証明する sin(pi*x)+sin(pi*(10-x))=0provesin(π⋅x)+sin(π⋅(10−x))=0証明する cot(2θ)= 1/2 (tan(θ)-cot(θ))provecot(2θ)=21​(tan(θ)−cot(θ))証明する sin(4x)=(2)(sin(2x))(cos(2x))provesin(4x)=(2)(sin(2x))(cos(2x))
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