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受欢迎的 三角函数 >

(cos(x))/(sec(x))-(sin(x))/(csc(x))=1

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解答

sec(x)cos(x)​−csc(x)sin(x)​=1

解答

x∈R无解
求解步骤
sec(x)cos(x)​−csc(x)sin(x)​=1
两边减去 1sec(x)cos(x)​−csc(x)sin(x)​−1=0
化简 sec(x)cos(x)​−csc(x)sin(x)​−1:sec(x)csc(x)cos(x)csc(x)−sin(x)sec(x)−sec(x)csc(x)​
sec(x)cos(x)​−csc(x)sin(x)​−1
将项转换为分式: 1=11​=sec(x)cos(x)​−csc(x)sin(x)​−11​
sec(x),csc(x),1的最小公倍数:sec(x)csc(x)
sec(x),csc(x),1
最小公倍数 (LCM)
计算出由至少在以下一个因式表达式中出现的因子组成的表达式=sec(x)csc(x)
根据最小公倍数调整分式
将每个分子乘以其分母转变为最小公倍数所要乘以的同一数值 sec(x)csc(x)
对于 sec(x)cos(x)​:将分母和分子乘以 csc(x)sec(x)cos(x)​=sec(x)csc(x)cos(x)csc(x)​
对于 csc(x)sin(x)​:将分母和分子乘以 sec(x)csc(x)sin(x)​=csc(x)sec(x)sin(x)sec(x)​
对于 11​:将分母和分子乘以 sec(x)csc(x)11​=1⋅sec(x)csc(x)1⋅sec(x)csc(x)​=sec(x)csc(x)sec(x)csc(x)​
=sec(x)csc(x)cos(x)csc(x)​−csc(x)sec(x)sin(x)sec(x)​−sec(x)csc(x)sec(x)csc(x)​
因为分母相等,所以合并分式: ca​±cb​=ca±b​=sec(x)csc(x)cos(x)csc(x)−sin(x)sec(x)−sec(x)csc(x)​
sec(x)csc(x)cos(x)csc(x)−sin(x)sec(x)−sec(x)csc(x)​=0
g(x)f(x)​=0⇒f(x)=0cos(x)csc(x)−sin(x)sec(x)−sec(x)csc(x)=0
用 sin, cos 表示
cos(x)csc(x)−csc(x)sec(x)−sec(x)sin(x)
使用基本三角恒等式: csc(x)=sin(x)1​=cos(x)sin(x)1​−sin(x)1​sec(x)−sec(x)sin(x)
使用基本三角恒等式: sec(x)=cos(x)1​=cos(x)sin(x)1​−sin(x)1​⋅cos(x)1​−cos(x)1​sin(x)
化简 cos(x)sin(x)1​−sin(x)1​⋅cos(x)1​−cos(x)1​sin(x):sin(x)cos(x)cos2(x)−1−sin2(x)​
cos(x)sin(x)1​−sin(x)1​⋅cos(x)1​−cos(x)1​sin(x)
cos(x)sin(x)1​=sin(x)cos(x)​
cos(x)sin(x)1​
分式相乘: a⋅cb​=ca⋅b​=sin(x)1⋅cos(x)​
乘以:1⋅cos(x)=cos(x)=sin(x)cos(x)​
sin(x)1​⋅cos(x)1​=sin(x)cos(x)1​
sin(x)1​⋅cos(x)1​
分式相乘: ba​⋅dc​=b⋅da⋅c​=sin(x)cos(x)1⋅1​
数字相乘:1⋅1=1=sin(x)cos(x)1​
cos(x)1​sin(x)=cos(x)sin(x)​
cos(x)1​sin(x)
分式相乘: a⋅cb​=ca⋅b​=cos(x)1⋅sin(x)​
乘以:1⋅sin(x)=sin(x)=cos(x)sin(x)​
=sin(x)cos(x)​−sin(x)cos(x)1​−cos(x)sin(x)​
sin(x),sin(x)cos(x),cos(x)的最小公倍数:sin(x)cos(x)
sin(x),sin(x)cos(x),cos(x)
最小公倍数 (LCM)
计算出由至少在以下一个因式表达式中出现的因子组成的表达式=sin(x)cos(x)
根据最小公倍数调整分式
将每个分子乘以其分母转变为最小公倍数所要乘以的同一数值 sin(x)cos(x)
对于 sin(x)cos(x)​:将分母和分子乘以 cos(x)sin(x)cos(x)​=sin(x)cos(x)cos(x)cos(x)​=sin(x)cos(x)cos2(x)​
对于 cos(x)sin(x)​:将分母和分子乘以 sin(x)cos(x)sin(x)​=cos(x)sin(x)sin(x)sin(x)​=sin(x)cos(x)sin2(x)​
=sin(x)cos(x)cos2(x)​−sin(x)cos(x)1​−sin(x)cos(x)sin2(x)​
因为分母相等,所以合并分式: ca​±cb​=ca±b​=sin(x)cos(x)cos2(x)−1−sin2(x)​
=sin(x)cos(x)cos2(x)−1−sin2(x)​
cos(x)sin(x)−1+cos2(x)−sin2(x)​=0
g(x)f(x)​=0⇒f(x)=0−1+cos2(x)−sin2(x)=0
使用三角恒等式改写
−1+cos2(x)−sin2(x)
使用倍角公式: cos2(x)−sin2(x)=cos(2x)=−1+cos(2x)
−1+cos(2x)=0
将 1到右边
−1+cos(2x)=0
两边加上 1−1+cos(2x)+1=0+1
化简cos(2x)=1
cos(2x)=1
cos(2x)=1的通解
cos(x) 周期表(周期为 2πn):
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
2x=0+2πn
2x=0+2πn
解 2x=0+2πn:x=πn
2x=0+2πn
0+2πn=2πn2x=2πn
两边除以 2
2x=2πn
两边除以 222x​=22πn​
化简x=πn
x=πn
x=πn
因为方程对以下值无定义:πnx∈R无解

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tan(x)= 12/35tan(x)=3512​4=sec(θ)4=sec(θ)1+sqrt(2)sin(x)=cos(2x)1+2​sin(x)=cos(2x)12-sin(θ)=cos(2θ)12−sin(θ)=cos(2θ)2cos(θ)=32cos(θ)=3
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