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受欢迎的三角函数 >

tan(x)=5sin(x)

解答

tan (x) = 5 sin (x)

解答

x = 2 πn, x = π + 2 πn, x = 1.36943 \dots + 2 πn, x = 2 π - 1.36943 \dots + 2 πn

+1

度数

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n, x = 78.46304 \dots^{\circ} + 36 0^{\circ} n, x = 281.53695 \dots^{\circ} + 36 0^{\circ} n

求解步骤

tan (x) = 5 sin (x)

两边减去

5 sin (x)

tan (x) - 5 sin (x) = 0

用 sin, cos 表示

tan (x) - 5 sin (x)

使用基本三角恒等式:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{sin ( x )}{cos ( x )} - 5 sin (x)

化简

\frac{sin ( x )}{cos ( x )} - 5 sin (x) : \frac{sin ( x ) - 5 sin ( x ) cos ( x )}{cos ( x )}

\frac{sin ( x )}{cos ( x )} - 5 sin (x)

将项转换为分式:

5 sin (x) = \frac{5 sin ( x ) cos ( x )}{cos ( x )}

= \frac{sin ( x )}{cos ( x )} - \frac{5 sin ( x ) cos ( x )}{cos ( x )}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ( x ) - 5 sin ( x ) cos ( x )}{cos ( x )}

= \frac{sin ( x ) - 5 sin ( x ) cos ( x )}{cos ( x )}

\frac{sin ( x ) - 5 cos ( x ) sin ( x )}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

sin (x) - 5 cos (x) sin (x) = 0

分解

sin (x) - 5 cos (x) sin (x) : - sin (x) (5 cos (x) - 1)

sin (x) - 5 cos (x) sin (x)

因式分解出通项

- sin (x)

= - sin (x) (- 1 + 5 cos (x))

- sin (x) (5 cos (x) - 1) = 0

分别求解每个部分

sin (x) = 0 or 5 cos (x) - 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

sin (x) = 0

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

解

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

5 cos (x) - 1 = 0 : x = arccos (\frac{1}{5}) + 2 πn, x = 2 π - arccos (\frac{1}{5}) + 2 πn

5 cos (x) - 1 = 0

将

1

到右边

5 cos (x) - 1 = 0

两边加上

1

5 cos (x) - 1 + 1 = 0 + 1

化简

5 cos (x) = 1

5 cos (x) = 1

两边除以

5

5 cos (x) = 1

两边除以

5

\frac{5 cos ( x )}{5} = \frac{1}{5}

化简

cos (x) = \frac{1}{5}

cos (x) = \frac{1}{5}

使用反三角函数性质

cos (x) = \frac{1}{5}

cos (x) = \frac{1}{5}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{1}{5}) + 2 πn, x = 2 π - arccos (\frac{1}{5}) + 2 πn

x = arccos (\frac{1}{5}) + 2 πn, x = 2 π - arccos (\frac{1}{5}) + 2 πn

合并所有解

x = 2 πn, x = π + 2 πn, x = arccos (\frac{1}{5}) + 2 πn, x = 2 π - arccos (\frac{1}{5}) + 2 πn

以小数形式表示解

x = 2 πn, x = π + 2 πn, x = 1.36943 \dots + 2 πn, x = 2 π - 1.36943 \dots + 2 πn

作图

流行的例子

cot^2(x)=-2cot(x)-1

cot^{2} (x) = - 2 cot (x) - 1

cos (\frac{π t}{2}) = 0

sin (θ) = - \frac{3}{7}

tan(θ)=(sqrt(3))/(-1)

tan (θ) = \frac{3}{- 1}

cos (x) = \frac{8}{10}