解答
sin(x)=2⋅sin(3x)
解答
x=2πn,x=π+2πn,x=−0.91173…+2πn,x=π+0.91173…+2πn,x=0.91173…+2πn,x=π−0.91173…+2πn
+1
度数
x=0∘+360∘n,x=180∘+360∘n,x=−52.23875…∘+360∘n,x=232.23875…∘+360∘n,x=52.23875…∘+360∘n,x=127.76124…∘+360∘n求解步骤
sin(x)=2sin(3x)
两边减去 2sin(3x)sin(x)−2sin(3x)=0
使用三角恒等式改写
sin(x)−2sin(3x)
sin(3x)=3sin(x)−4sin3(x)
sin(3x)
使用三角恒等式改写
sin(3x)
改写为=sin(2x+x)
使用角和恒等式: sin(s+t)=sin(s)cos(t)+cos(s)sin(t)=sin(2x)cos(x)+cos(2x)sin(x)
使用倍角公式: sin(2x)=2sin(x)cos(x)=cos(2x)sin(x)+cos(x)2sin(x)cos(x)
化简 cos(2x)sin(x)+cos(x)⋅2sin(x)cos(x):sin(x)cos(2x)+2cos2(x)sin(x)
cos(2x)sin(x)+cos(x)2sin(x)cos(x)
cos(x)⋅2sin(x)cos(x)=2cos2(x)sin(x)
cos(x)2sin(x)cos(x)
使用指数法则: ab⋅ac=ab+ccos(x)cos(x)=cos1+1(x)=2sin(x)cos1+1(x)
数字相加:1+1=2=2sin(x)cos2(x)
=sin(x)cos(2x)+2cos2(x)sin(x)
=sin(x)cos(2x)+2cos2(x)sin(x)
=sin(x)cos(2x)+2cos2(x)sin(x)
使用倍角公式: cos(2x)=1−2sin2(x)=(1−2sin2(x))sin(x)+2cos2(x)sin(x)
使用毕达哥拉斯恒等式: cos2(x)+sin2(x)=1cos2(x)=1−sin2(x)=(1−2sin2(x))sin(x)+2(1−sin2(x))sin(x)
乘开 (1−2sin2(x))sin(x)+2(1−sin2(x))sin(x):−4sin3(x)+3sin(x)
(1−2sin2(x))sin(x)+2(1−sin2(x))sin(x)
=sin(x)(1−2sin2(x))+2sin(x)(1−sin2(x))
乘开 sin(x)(1−2sin2(x)):sin(x)−2sin3(x)
sin(x)(1−2sin2(x))
使用分配律: a(b−c)=ab−aca=sin(x),b=1,c=2sin2(x)=sin(x)1−sin(x)2sin2(x)
=1sin(x)−2sin2(x)sin(x)
化简 1⋅sin(x)−2sin2(x)sin(x):sin(x)−2sin3(x)
1sin(x)−2sin2(x)sin(x)
1⋅sin(x)=sin(x)
1sin(x)
乘以:1⋅sin(x)=sin(x)=sin(x)
2sin2(x)sin(x)=2sin3(x)
2sin2(x)sin(x)
使用指数法则: ab⋅ac=ab+csin2(x)sin(x)=sin2+1(x)=2sin2+1(x)
数字相加:2+1=3=2sin3(x)
=sin(x)−2sin3(x)
=sin(x)−2sin3(x)
=sin(x)−2sin3(x)+2(1−sin2(x))sin(x)
乘开 2sin(x)(1−sin2(x)):2sin(x)−2sin3(x)
2sin(x)(1−sin2(x))
使用分配律: a(b−c)=ab−aca=2sin(x),b=1,c=sin2(x)=2sin(x)1−2sin(x)sin2(x)
=2⋅1sin(x)−2sin2(x)sin(x)
化简 2⋅1⋅sin(x)−2sin2(x)sin(x):2sin(x)−2sin3(x)
2⋅1sin(x)−2sin2(x)sin(x)
2⋅1⋅sin(x)=2sin(x)
2⋅1sin(x)
数字相乘:2⋅1=2=2sin(x)
2sin2(x)sin(x)=2sin3(x)
2sin2(x)sin(x)
使用指数法则: ab⋅ac=ab+csin2(x)sin(x)=sin2+1(x)=2sin2+1(x)
数字相加:2+1=3=2sin3(x)
=2sin(x)−2sin3(x)
=2sin(x)−2sin3(x)
=sin(x)−2sin3(x)+2sin(x)−2sin3(x)
化简 sin(x)−2sin3(x)+2sin(x)−2sin3(x):−4sin3(x)+3sin(x)
sin(x)−2sin3(x)+2sin(x)−2sin3(x)
对同类项分组=−2sin3(x)−2sin3(x)+sin(x)+2sin(x)
同类项相加:−2sin3(x)−2sin3(x)=−4sin3(x)=−4sin3(x)+sin(x)+2sin(x)
同类项相加:sin(x)+2sin(x)=3sin(x)=−4sin3(x)+3sin(x)
=−4sin3(x)+3sin(x)
=−4sin3(x)+3sin(x)
=sin(x)−2(3sin(x)−4sin3(x))
化简 sin(x)−2(3sin(x)−4sin3(x)):−5sin(x)+8sin3(x)
sin(x)−2(3sin(x)−4sin3(x))
乘开 −2(3sin(x)−4sin3(x)):−6sin(x)+8sin3(x)
−2(3sin(x)−4sin3(x))
使用分配律: a(b−c)=ab−aca=−2,b=3sin(x),c=4sin3(x)=−2⋅3sin(x)−(−2)⋅4sin3(x)
使用加减运算法则−(−a)=a=−2⋅3sin(x)+2⋅4sin3(x)
化简 −2⋅3sin(x)+2⋅4sin3(x):−6sin(x)+8sin3(x)
−2⋅3sin(x)+2⋅4sin3(x)
数字相乘:2⋅3=6=−6sin(x)+2⋅4sin3(x)
数字相乘:2⋅4=8=−6sin(x)+8sin3(x)
=−6sin(x)+8sin3(x)
=sin(x)−6sin(x)+8sin3(x)
同类项相加:sin(x)−6sin(x)=−5sin(x)=−5sin(x)+8sin3(x)
=−5sin(x)+8sin3(x)
−5sin(x)+8sin3(x)=0
用替代法求解
−5sin(x)+8sin3(x)=0
令:sin(x)=u−5u+8u3=0
−5u+8u3=0:u=0,u=−410,u=410
−5u+8u3=0
因式分解 −5u+8u3:u(22u+5)(22u−5)
−5u+8u3
因式分解出通项 u:u(8u2−5)
8u3−5u
使用指数法则: ab+c=abacu3=u2u=8u2u−5u
因式分解出通项 u=u(8u2−5)
=u(8u2−5)
分解 8u2−5:(8u+5)(8u−5)
8u2−5
将 8u2−5 改写为 (8u)2−(5)2
8u2−5
使用根式运算法则: a=(a)28=(8)2=(8)2u2−5
使用根式运算法则: a=(a)25=(5)2=(8)2u2−(5)2
使用指数法则: ambm=(ab)m(8)2u2=(8u)2=(8u)2−(5)2
=(8u)2−(5)2
使用平方差公式: x2−y2=(x+y)(x−y)(8u)2−(5)2=(8u+5)(8u−5)=(8u+5)(8u−5)
=u(8u+5)(8u−5)
整理后得=u(22u+5)(22u−5)
u(22u+5)(22u−5)=0
使用零因数法则: If ab=0then a=0or b=0u=0or22u+5=0or22u−5=0
解 22u+5=0:u=−410
22u+5=0
将 5到右边
22u+5=0
两边减去 522u+5−5=0−5
化简22u=−5
22u=−5
两边除以 22
22u=−5
两边除以 222222u=22−5
化简
2222u=22−5
化简 2222u:u
2222u
数字相除:22=1=22u
约分:2=u
化简 22−5:−410
22−5
使用分式法则: b−a=−ba=−225
−225有理化:−410
−225
乘以共轭根式 22=−22252
52=10
52
使用根式运算法则: ab=a⋅b52=5⋅2=5⋅2
数字相乘:5⋅2=10=10
222=4
222
使用指数法则: ab⋅ac=ab+c222=2⋅221⋅221=21+21+21=21+21+21
同类项相加:21+21=2⋅21=21+2⋅21
2⋅21=1
2⋅21
分式相乘: a⋅cb=ca⋅b=21⋅2
约分:2=1
=21+1
数字相加:1+1=2=22
22=4=4
=−410
=−410
u=−410
u=−410
u=−410
解 22u−5=0:u=410
22u−5=0
将 5到右边
22u−5=0
两边加上 522u−5+5=0+5
化简22u=5
22u=5
两边除以 22
22u=5
两边除以 222222u=225
化简
2222u=225
化简 2222u:u
2222u
数字相除:22=1=22u
约分:2=u
化简 225:410
225
乘以共轭根式 22=22252
52=10
52
使用根式运算法则: ab=a⋅b52=5⋅2=5⋅2
数字相乘:5⋅2=10=10
222=4
222
使用指数法则: ab⋅ac=ab+c222=2⋅221⋅221=21+21+21=21+21+21
同类项相加:21+21=2⋅21=21+2⋅21
2⋅21=1
2⋅21
分式相乘: a⋅cb=ca⋅b=21⋅2
约分:2=1
=21+1
数字相加:1+1=2=22
22=4=4
=410
u=410
u=410
u=410
解为u=0,u=−410,u=410
u=sin(x)代回sin(x)=0,sin(x)=−410,sin(x)=410
sin(x)=0,sin(x)=−410,sin(x)=410
sin(x)=0:x=2πn,x=π+2πn
sin(x)=0
sin(x)=0的通解
sin(x) 周期表(周期为 2πn"):
x06π4π3π2π32π43π65πsin(x)02122231232221xπ67π45π34π23π35π47π611πsin(x)0−21−22−23−1−23−22−21
x=0+2πn,x=π+2πn
x=0+2πn,x=π+2πn
解 x=0+2πn:x=2πn
x=0+2πn
0+2πn=2πnx=2πn
x=2πn,x=π+2πn
sin(x)=−410:x=arcsin(−410)+2πn,x=π+arcsin(410)+2πn
sin(x)=−410
使用反三角函数性质
sin(x)=−410
sin(x)=−410的通解sin(x)=−a⇒x=arcsin(−a)+2πn,x=π+arcsin(a)+2πnx=arcsin(−410)+2πn,x=π+arcsin(410)+2πn
x=arcsin(−410)+2πn,x=π+arcsin(410)+2πn
sin(x)=410:x=arcsin(410)+2πn,x=π−arcsin(410)+2πn
sin(x)=410
使用反三角函数性质
sin(x)=410
sin(x)=410的通解sin(x)=a⇒x=arcsin(a)+2πn,x=π−arcsin(a)+2πnx=arcsin(410)+2πn,x=π−arcsin(410)+2πn
x=arcsin(410)+2πn,x=π−arcsin(410)+2πn
合并所有解x=2πn,x=π+2πn,x=arcsin(−410)+2πn,x=π+arcsin(410)+2πn,x=arcsin(410)+2πn,x=π−arcsin(410)+2πn
以小数形式表示解x=2πn,x=π+2πn,x=−0.91173…+2πn,x=π+0.91173…+2πn,x=0.91173…+2πn,x=π−0.91173…+2πn