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Frequently Asked Questions (FAQ)
What is the derivative of y=tan(ln(ax+b)) ?
- The derivative of y=tan(ln(ax+b)) is (asec^2(ln(ax+b)))/(ax+b)
What is the first derivative of y=tan(ln(ax+b)) ?
- The first derivative of y=tan(ln(ax+b)) is (asec^2(ln(ax+b)))/(ax+b)