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Popular Geometry Problems
(x+2)^2+((y-1)/2)^2=2^2
(x+2)^{2}+(\frac{y-1}{2})^{2}=2^{2}
(((x+5)^2)}{10}+\frac{((y+4)^2))/8 =1
\frac{((x+5)^{2})}{10}+\frac{((y+4)^{2})}{8}=1
3x^2+y^2=25
3x^{2}+y^{2}=25
2x^2+9y^2-12x-18y+9=0
2x^{2}+9y^{2}-12x-18y+9=0
(x^2)/(100)+(y^2)/(144)=1
\frac{x^{2}}{100}+\frac{y^{2}}{144}=1
3x^2+2y^2-17x=0
3x^{2}+2y^{2}-17x=0
x^2+4y^2+10x+24y+25=0
x^{2}+4y^{2}+10x+24y+25=0
(x-3)^2+4(y+1)^2=1
(x-3)^{2}+4(y+1)^{2}=1
(x^2)/8+(y^2)/a =1
\frac{x^{2}}{8}+\frac{y^{2}}{a}=1
2x^2+4y^2+6x-8y-5=0
2x^{2}+4y^{2}+6x-8y-5=0
1-x^2-y^2=5
1-x^{2}-y^{2}=5
36(x-1/2)^2-1/4+64(y+2)^2-4+265=576
36(x-\frac{1}{2})^{2}-\frac{1}{4}+64(y+2)^{2}-4+265=576
(x^2)/(4^2)+(y^2)/(6^2)=1
\frac{x^{2}}{4^{2}}+\frac{y^{2}}{6^{2}}=1
7x^2+y^2=8
7x^{2}+y^{2}=8
9x^2+16y^2-54x+32y-47=0
9x^{2}+16y^{2}-54x+32y-47=0
4x^2+32x+9y^2-18y+37=0
4x^{2}+32x+9y^{2}-18y+37=0
x^2+4y^2-6x+40y+105=0
x^{2}+4y^{2}-6x+40y+105=0
solvefor x,(x^2}{16}+\frac{Y(x)^2)/9 =1
solvefor\:x,\frac{x^{2}}{16}+\frac{Y(x)^{2}}{9}=1
9(5.66-2)x^2+y^2=36
9(5.66-2)x^{2}+y^{2}=36
9x^2-36x+25y^2+150y+36=0
9x^{2}-36x+25y^{2}+150y+36=0
(x^2)/(12)+(y^2)/(144)= y/(12)
\frac{x^{2}}{12}+\frac{y^{2}}{144}=\frac{y}{12}
2x^2+5y^2-6x-2y+4=0
2x^{2}+5y^{2}-6x-2y+4=0
9x^2+36x+4y^2-24y+36=0
9x^{2}+36x+4y^{2}-24y+36=0
((x-1)^2)/3+((y-1)^2)/(25)=1
\frac{(x-1)^{2}}{3}+\frac{(y-1)^{2}}{25}=1
((x-4)^2)/(16)+((y+2)^2)/(36)=1
\frac{(x-4)^{2}}{16}+\frac{(y+2)^{2}}{36}=1
((x-4)^2}{4.5}+\frac{(y-1)^2)/1 =1
\frac{(x-4)^{2}}{4.5}+\frac{(y-1)^{2}}{1}=1
y=(2x-4)/(-2y+4)x+6
y=\frac{2x-4}{-2y+4}x+6
x^2+4y^2+9x+10y-14=0
x^{2}+4y^{2}+9x+10y-14=0
((x+1)^2)/4+((y-3/2)^2)/8 =1
\frac{(x+1)^{2}}{4}+\frac{(y-\frac{3}{2})^{2}}{8}=1
((x-2)^2)/(4^2)+((y-3)^2)/(5^2)=1
\frac{(x-2)^{2}}{4^{2}}+\frac{(y-3)^{2}}{5^{2}}=1
25x^2+9y^2-25=0
25x^{2}+9y^{2}-25=0
y^2+5/2 y+(x^2)/4-44=0
y^{2}+\frac{5}{2}y+\frac{x^{2}}{4}-44=0
(x^2)/(100)+(y^2)/(52)=1
\frac{x^{2}}{100}+\frac{y^{2}}{52}=1
((x-14)^2)/3+((y-11)^2)/4 =1
\frac{(x-14)^{2}}{3}+\frac{(y-11)^{2}}{4}=1
x^2+7y^2=12
x^{2}+7y^{2}=12
((x-3)^2)/(64)+((y+1)^2)/(25)=1
\frac{(x-3)^{2}}{64}+\frac{(y+1)^{2}}{25}=1
(x^2}{25}+\frac{y^2)/9 <1
\frac{x^{2}}{25}+\frac{y^{2}}{9}<1
((x+4)^2)/4+((y-2)^2)/3 =1
\frac{(x+4)^{2}}{4}+\frac{(y-2)^{2}}{3}=1
(x^2)/9+(y^2)/(9/25)=1
\frac{x^{2}}{9}+\frac{y^{2}}{\frac{9}{25}}=1
y=4-(x^2)/(4y)
y=4-\frac{x^{2}}{4y}
3x^2+y^2-12=0
3x^{2}+y^{2}-12=0
4y^2+x^2-2x=3
4y^{2}+x^{2}-2x=3
((x)^2)/(49)+((y)^2)/(25)=1
\frac{(x)^{2}}{49}+\frac{(y)^{2}}{25}=1
((-y))/(-2-x)=((-1))/(\frac{(4-y)){6-x}}
\frac{(-y)}{-2-x}=\frac{(-1)}{\frac{(4-y)}{6-x}}
9(x+9)^2+4(y-12)^2=1284
9(x+9)^{2}+4(y-12)^{2}=1284
(x-4)^2+y^2= 1/4 ((x+2)^2+(y-y))
(x-4)^{2}+y^{2}=\frac{1}{4}((x+2)^{2}+(y-y))
((x-2)^2)/9+((y+2)^2)/(25)=1
\frac{(x-2)^{2}}{9}+\frac{(y+2)^{2}}{25}=1
x^2+4y^2+10x+8y-13=0
x^{2}+4y^{2}+10x+8y-13=0
25x^2+4y^2-100x+8y+91=0
25x^{2}+4y^{2}-100x+8y+91=0
4x^2+9y^2-54y+45=0
4x^{2}+9y^{2}-54y+45=0
x^2+4y^2=5
x^{2}+4y^{2}=5
3x^2+4y^2+18x+8y+19=0
3x^{2}+4y^{2}+18x+8y+19=0
((x+3)^2)/4+((y+2)^2)/(16)=1
\frac{(x+3)^{2}}{4}+\frac{(y+2)^{2}}{16}=1
(x^2)/2+(y^2)/1 =1
\frac{x^{2}}{2}+\frac{y^{2}}{1}=1
(-x^2)/(2^2)-(y^2)/(4^2)=1
\frac{-x^{2}}{2^{2}}-\frac{y^{2}}{4^{2}}=1
((x-3)^2)/4+((y+8)^2)/(16)=1
\frac{(x-3)^{2}}{4}+\frac{(y+8)^{2}}{16}=1
36(x+2)^2+(y-4)^2=72
36(x+2)^{2}+(y-4)^{2}=72
((x-2)^2)/4+(y^2)/(33)=1
\frac{(x-2)^{2}}{4}+\frac{y^{2}}{33}=1
((x+1)^2)/(21)+((y+5)^2)/(25)=1
\frac{(x+1)^{2}}{21}+\frac{(y+5)^{2}}{25}=1
4x^2+3y^2=7
4x^{2}+3y^{2}=7
25x^2+4y^2-250x-16y=-541
25x^{2}+4y^{2}-250x-16y=-541
x^2+(z^2)/(225)=1
x^{2}+\frac{z^{2}}{225}=1
4x^2+12y^2-4x-24y+1=0
4x^{2}+12y^{2}-4x-24y+1=0
(x^2)/4+x+9y^2+18y+31/4 =0
\frac{x^{2}}{4}+x+9y^{2}+18y+\frac{31}{4}=0
15x^2+9y^2=225
15x^{2}+9y^{2}=225
4x^2+y^2>1
4x^{2}+y^{2}>1
y+x-3=3y^2+2x^2
y+x-3=3y^{2}+2x^{2}
4(x-1)^2+y^2=36
4(x-1)^{2}+y^{2}=36
3(3x^{(2)}+9y^{(2)}-2x-36)=-82
3(3x^{(2)}+9y^{(2)}-2x-36)=-82
([(x-1)^2]}{25}+\frac{[(y+3)^2])/9 =1
\frac{[(x-1)^{2}]}{25}+\frac{[(y+3)^{2}]}{9}=1
25(x^2+4x+4)+36(y^2+2y+1)=770
25(x^{2}+4x+4)+36(y^{2}+2y+1)=770
((x-3)^2}{25}+\frac{(y-1)^2)/9 =1
\frac{(x-3)^{2}}{25}+\frac{(y-1)^{2}}{9}=1
9x^2-18x+4y^2+24y=-9
9x^{2}-18x+4y^{2}+24y=-9
x/(x^2+y^2)=2
\frac{x}{x^{2}+y^{2}}=2
(x^2)/(200)+(y^2)/(50)=1
\frac{x^{2}}{200}+\frac{y^{2}}{50}=1
(x^2)/(81)+(y^2)/(144)=1
\frac{x^{2}}{81}+\frac{y^{2}}{144}=1
4x^2+9y^2=1-x-y
4x^{2}+9y^{2}=1-x-y
4x^2+y^2=4y
4x^{2}+y^{2}=4y
(1+y^2)/(1-x^2)=2
\frac{1+y^{2}}{1-x^{2}}=2
-x^2-(y^2)/(49)=1
-x^{2}-\frac{y^{2}}{49}=1
((x+7)^2)/(144)+((y+2)^2)/(100)=1
\frac{(x+7)^{2}}{144}+\frac{(y+2)^{2}}{100}=1
(x^2)/(36)+((y+9)^2)/(81)=1
\frac{x^{2}}{36}+\frac{(y+9)^{2}}{81}=1
4x^2+18y^2=36
4x^{2}+18y^{2}=36
(x-3)^2+((y+1)^2)/(49)=1
(x-3)^{2}+\frac{(y+1)^{2}}{49}=1
22y^2+32x^2-308y-512x+2.422=0
22y^{2}+32x^{2}-308y-512x+2.422=0
-3y^2-3x^2+5x+10y=5x^2+1
-3y^{2}-3x^{2}+5x+10y=5x^{2}+1
x/((x^2+y^2))=-1
\frac{x}{(x^{2}+y^{2})}=-1
((x-5)/5)^2+((y+7)/(16))^2=1
(\frac{x-5}{5})^{2}+(\frac{y+7}{16})^{2}=1
2x^2+4y^2+18x+24y+44=0
2x^{2}+4y^{2}+18x+24y+44=0
(x+1)^2+((y-1)^2)/(16)=1
(x+1)^{2}+\frac{(y-1)^{2}}{16}=1
10x^2+40x+7y^2+70y+145=0
10x^{2}+40x+7y^{2}+70y+145=0
4x^2+4y^2=100-20x+x^2
4x^{2}+4y^{2}=100-20x+x^{2}
6=x^2+9y^2
6=x^{2}+9y^{2}
1=((x-3)^2}{16}+\frac{y^2)/4
1=\frac{(x-3)^{2}}{16}+\frac{y^{2}}{4}
(3x-3)^2+(-2y-4)^2=43+9+16
(3x-3)^{2}+(-2y-4)^{2}=43+9+16
36x^2+81y^2=49
36x^{2}+81y^{2}=49
49x^2+16y^2-784=0
49x^{2}+16y^{2}-784=0
9x^2+4y^2-54x-16y+61=0
9x^{2}+4y^{2}-54x-16y+61=0
(y^2}{16}+\frac{z^2)/9 =1
\frac{y^{2}}{16}+\frac{z^{2}}{9}=1
(x-4)^2+2(y-3)^2=1
(x-4)^{2}+2(y-3)^{2}=1
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