y^2=8(x+3)

Lösung

y^{2} = 8 (x + 3)

(h, k) = (- 3, 0), p = 2

Schritte zur Lösung

y^{2} = 8 (x + 3)

Rewrite

y^{2} = 8 (x + 3)

in the standard form:

4 \cdot 2 (x - (- 3)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 3, 0), p = 2

y \geq - 4 x^{2} - 12 x - 8

x^{2} + 10 x - 2 y + 21 = 0

x = \frac{5}{2} y^{2} - 3

y^{2} < x

x^{2} = 7 y