x= 5/2 y^2-3

Lösung

x = \frac{5}{2} y^{2} - 3

(h, k) = (- 3, 0), p = \frac{1}{10}

Schritte zur Lösung

x = \frac{5}{2} y^{2} - 3

Rewrite

x = \frac{5}{2} y^{2} - 3

in the standard form:

4 \cdot \frac{1}{10} (x - (- 3)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 3, 0), p = \frac{1}{10}

y^{2} < x

x^{2} = 7 y

x^{2} - 8 y - 4 = 0

x + y^{2} + 14 x - 14 y + 73 = 0

y - 2 x^{2} + 12 x + 8 = 0