8x+2y^2=3x^2+3y

解

8 x + 2 y^{2} = 3 x^{2} + 3 y

(h, k) = (\frac{4}{3}, \frac{3}{4}), a = \frac{101}{6 2}, b = \frac{101}{4 3}

解答ステップ

8 x + 2 y^{2} = 3 x^{2} + 3 y

8 x + 2 y^{2} = 3 x^{2} + 3 y

を標準的な双曲線のequationで書き換える

\frac{( x - \frac{4}{3} ) ^{2}}{( \frac{101}{6 2} ) ^{2}} - \frac{( y - \frac{3}{4} ) ^{2}}{( \frac{101}{4 3} ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (\frac{4}{3}, \frac{3}{4}), a = \frac{101}{6 2}, b = \frac{101}{4 3}