3x^{(2)}-12y^{(2)}+48=0

解答

3 x^{(2)} - 12 y^{(2)} + 48 = 0

(h, k) = (0, 0), a = 2, b = 4

求解步骤

3 x^{2} - 12 y^{2} + 48 = 0

将

3 x^{2} - 12 y^{2} + 48 = 0

改写为标准双曲线方程形式

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (0, 0), a = 2, b = 4

- 9 y^{2} + z^{2} = 36

3 x^{2} - y^{2} + 3 x + 4 y - 3 = 0

\frac{( x - 3 ) ^{2}}{10} - \frac{( y + 5 ) ^{2}}{9} = 4

so l v e f or x, 12 Y (x)^{2} - 15 x^{2} = 180

9 x^{2} - 16 y^{2} - 90 x - 96 y - 63 = 0