exzentrizität ((x-4)^2)/3+(y^2)/3 =1

Lösung

exzentrizität

\frac{( x - 4 ) ^{2}}{3} + \frac{y ^{2}}{3} = 1

0

Schritte zur Lösung

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{( x - 4 ) ^{2}}{3} + \frac{y ^{2}}{3} = 1 :

Ellipse with center

(h, k) = (4, 0), b = 3, a = 3

= \frac{( 3 ) ^{2} - ( 3 ) ^{2}}{3}

\frac{( 3 ) ^{2} - ( 3 ) ^{2}}{3} = 0

= 0

ecce n t r i c i t y 9 x^{2} + 16 y^{2} - 36 x + 96 y + 36 = 0

ecce n t r i c i t y 4 x^{2} + 25 y^{2} - 40 x + 150 y + 225 = 0

ecce n t r i c i t y \frac{x ^{2}}{9} + \frac{y ^{2}}{49} = 1

ecce n t r i c i t y \frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

ecce n t r i c i t y \frac{x ^{2}}{9} + \frac{y ^{2}}{5} = 1