exzentrizität 2x^2+y^2=50

Lösung

exzentrizität

2 x^{2} + y^{2} = 50

\frac{1}{2}

Dezimale

0.70710 \dots

Schritte zur Lösung

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

2 x^{2} + y^{2} = 50 :

Ellipse with center

(h, k) = (0, 0), b = 52, a = 5

= \frac{( 5 2 ) ^{2} - 5 ^{2}}{5 2}

\frac{( 5 2 ) ^{2} - 5 ^{2}}{5 2} = \frac{1}{2}

= \frac{1}{2}

ecce n t r i c i t y 4 x^{2} + 3 y^{2} + 8 x - 24 y + 51 = 0

ecce n t r i c i t y \frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

ecce n t r i c i t y 4 x^{2} + y^{2} = 16

ecce n t r i c i t y x^{2} + y^{2} - 6 x - 8 y = 50

ecce n t r i c i t y \frac{x ^{2}}{4} + y^{2} = 1