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Beliebt Geometry >

center (x^2)/(25)+((y+3)^2)/(49)=1

Lösung

center

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

Lösung

(0, - 3)

Schritte zur Lösung

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, - 3), a = 5, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, - 3), b = 7, a = 5

And the center is:

(0, - 3)

Graph

Beliebte Beispiele

center 3x^2+y^2-24x+39=0

ce n t er 3 x^{2} + y^{2} - 24 x + 39 = 0

center ((x-3)^2)/(49)+((y+5)^2)/(25)=1

ce n t er \frac{( x - 3 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{25} = 1

center 2x^2+3y^2-4x+6y-1=0

ce n t er 2 x^{2} + 3 y^{2} - 4 x + 6 y - 1 = 0

center x^2+2y^2+2x-8y+7=0

ce n t er x^{2} + 2 y^{2} + 2 x - 8 y + 7 = 0

center 4x^2+25y^2=100

ce n t er 4 x^{2} + 25 y^{2} = 100