center 4x^2+25y^2=100

Lösung

center

4 x^{2} + 25 y^{2} = 100

(0, 0)

Schritte zur Lösung

4 x^{2} + 25 y^{2} = 100

Rewrite

4 x^{2} + 25 y^{2} = 100

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 2

And the center is:

(0, 0)

ce n t er \frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

ce n t er 25 x^{2} - 200 x + y^{2} + 4 y + 379 = 0

ce n t er 4 x^{2} + 9 y^{2} - 24 x + 72 y + 144 = 0

ce n t er \frac{x ^{2}}{64} + \frac{y ^{2}}{36} = 1

ce n t er \frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1