We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the vertices ((x+5)/4)^2+((y-4)/(16))^2=1 ?
- The vertices ((x+5)/4)^2+((y-4)/(16))^2=1 is (-5,20),(-5,-12)