(x^2)/(81/4)+(y^2)/(26/16)=1

Lösung

\frac{x ^{2}}{\frac{81}{4}} + \frac{y ^{2}}{\frac{26}{16}} = 1

(h, k) = (0, 0), a = \frac{9}{2}, b = \frac{13}{2 2}

Schritte zur Lösung

\frac{x ^{2}}{\frac{81}{4}} + \frac{y ^{2}}{\frac{26}{16}} = 1

Rewrite

\frac{x ^{2}}{\frac{81}{4}} + \frac{y ^{2}}{\frac{26}{16}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{9}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{13}{2 2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{9}{2}, b = \frac{13}{2 2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = \frac{9}{2}, b = \frac{13}{2 2}

25 x^{2} + 9 y^{2} + 200 x - 36 y + 211 = 0

4 x^{2} + 9 y^{2} - 8 x + 36 y + 4 = 0

- 5 x^{2} - 6 y^{2} = 1

\frac{( x + 2 ) ^{2}}{( - 13 ) ^{2}} + \frac{( y - 3 ) ^{2}}{( - 8 ) ^{2}} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 25