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Frequently Asked Questions (FAQ)
What is 4x^2+36x+4y^2-8y+68=x^2-6x+y^2-4y+13 ?
- The solution to 4x^2+36x+4y^2-8y+68=x^2-6x+y^2-4y+13 is Circle with (a,b)=(-7, 2/3),r=(2sqrt(70))/3