x^2+(y-1)^2=16

解答

x^{2} + (y - 1)^{2} = 16

(a, b) = (0, 1), r = 4

求解步骤

x^{2} + (y - 1)^{2} = 16

将

x^{2} + (y - 1)^{2} = 16

改写为圆标准方程

(x - 0)^{2} + (y - 1)^{2} = 4^{2}

因此圆的性质是:

(a, b) = (0, 1), r = 4

(x^{2} - 10 x + 25) + (y^{2} + 4 y + 4) = 36

x^{2} + y^{2} - 2 x - 2 y = 2

x^{2} + y^{2} - 6 x + 12 y + 41 = 0

(\frac{x - 19}{4})^{2} + (\frac{y - 9}{4})^{2} = 17

x^{2} + y^{2} + 4 x - 8 y + 16 = 0