What is the p(t)=(101)/(1+40e_{0.5)t} ?

The p(t)=(101)/(1+40e_{0.5)t} is Parity: Neither even nor odd Inverse: (101-t)/(40e_{0.5)t}

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p(t)=(101)/(1+40e_{0.5)t}

p (t) = \frac{101}{1 + 40 e _{0.5} t}

Parity : Neither even nor odd

Inverse : \frac{101 - t}{40 e _{0.5} t}

Solution steps

Parity of

\frac{101}{1 + 40 e _{0.5} t} :

Neither even nor odd

Inverse of

\frac{101}{1 + 40 e _{0.5} t} : \frac{101 - t}{40 e _{0.5} t}

f (a) = a^{3} - a^{2} - 2 a + 3

g (u) = (1 + u^{2})^{5} \cdot (4 - 7 u^{2})^{8}

y = sin (x) (ln (x))^{2}

f (x) = x + 769

f (x) = 2 x^{2} - 16 x + 125

What is the p(t)=(101)/(1+40e_{0.5)t} ?
The p(t)=(101)/(1+40e_{0.5)t} is Parity: Neither even nor odd<br/>Inverse: (101-t)/(40e_{0.5)t}