What is the general solution for roots (1+sin(x))/n ?

The general solution for roots (1+sin(x))/n is x=(3pi)/2+2pik

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roots (1+sin(x))/n

roots

\frac{1 + sin ( x )}{n}

x = \frac{3 π}{2} + 2 πk

Solution steps

\frac{1 + sin ( x )}{n}

The roots are the intercepts with the x-axis

(y = 0)

\frac{1 + sin ( x )}{n} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

1 + sin (x) = 0

Move

1

to the right side

sin (x) = - 1

General solutions for

sin (x) = - 1

x = \frac{3 π}{2} + 2 πk

f (x) = x^{2} - 4 x + 15

f (x) = 5 x^{3} - 8 x + 3 x^{5} + 4 x^{2} - 7 x^{4} + 1

f (x) = 7 x - 3 x^{3} - 5 x^{2} - 3

f (x) = lo g_{2} (cos^{2} (x))

y = 2 cos (x) - sin (x)

What is the general solution for roots (1+sin(x))/n ?
The general solution for roots (1+sin(x))/n is x=(3pi)/2+2pik