What is the y=((x^2-3x+1))/((sqrt(x-3))) ?

The y=((x^2-3x+1))/((sqrt(x-3))) is

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y=((x^2-3x+1))/((sqrt(x-3)))

y = \frac{( x ^{2} - 3 x + 1 )}{( x - 3 )}

Domain : x > 3

Range : f (x) \geq \frac{2 ( 1 + 21 )}{3 21 - 3}

Intercepts : None

Asymptotes : Vertical x = 3

Extreme Points : Minimum (\frac{15 + 21}{6}, \frac{2 ( 1 + 21 )}{3 21 - 3})

Interval Notation

Domain : (3, \infty)

Range : [\frac{2 ( 1 + 21 )}{3 21 - 3}, \infty)

Solution steps

Domain of

\frac{x ^{2} - 3 x + 1}{x - 3} : x > 3

Range of

\frac{x ^{2} - 3 x + 1}{x - 3} : f (x) \geq \frac{2 ( 1 + 21 )}{3 21 - 3}

Axis interception points of

\frac{x ^{2} - 3 x + 1}{x - 3} :

None

Asymptotes of

\frac{x ^{2} - 3 x + 1}{x - 3} :

Vertical

: x = 3

Extreme Points of

\frac{x ^{2} - 3 x + 1}{x - 3} :

Minimum

(\frac{15 + 21}{6}, \frac{2 ( 1 + 21 )}{3 21 - 3})

y = ln (\frac{( 3 - x )}{x})

p (x) = - x^{4} + 2 x^{3} - 4 x + 6

f (x) = (x - 2)^{4} \cdot (x + 1)^{3}

y = (1 + p) x + p^{2}

y = - 4 x^{3} + 30 x^{2} - 48 x - 1