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Popular >

f(x)=16x^4+16x^3-2x-1

Solution

f (x) = 16 x^{4} + 16 x^{3} - 2 x - 1

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq \frac{( 1 + 3 ) ^{4}}{16} - 3 - 3

X Intercepts : (0.43338 \dots, 0), (- 0.93338 \dots, 0), Y Intercepts : (0, - 1)

Asymptotes : None

Extreme Points : Minimum (- \frac{1 + 3}{4}, \frac{( 1 + 3 ) ^{4}}{16} - 3 - 3), Maximum (- \frac{1}{4}, - \frac{11}{16}), Minimum (\frac{- 1 + 3}{4}, \frac{( 3 - 1 ) ^{4}}{16} + 3 - 3)

+1

Solution steps

Domain of

16 x^{4} + 16 x^{3} - 2 x - 1 : - \infty < x < \infty

Range of

16 x^{4} + 16 x^{3} - 2 x - 1 : f (x) \geq \frac{( 1 + 3 ) ^{4}}{16} - 3 - 3

Axis interception points of

16 x^{4} + 16 x^{3} - 2 x - 1 :

X Intercepts

: (0.43338 \dots, 0), (- 0.93338 \dots, 0),

Y Intercepts

: (0, - 1)

Asymptotes of

16 x^{4} + 16 x^{3} - 2 x - 1 :

None

Extreme Points of

16 x^{4} + 16 x^{3} - 2 x - 1 :

Minimum

(- \frac{1 + 3}{4}, \frac{( 1 + 3 ) ^{4}}{16} - 3 - 3),

Maximum

(- \frac{1}{4}, - \frac{11}{16}),

Minimum

(\frac{- 1 + 3}{4}, \frac{( 3 - 1 ) ^{4}}{16} + 3 - 3)

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Frequently Asked Questions (FAQ)

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