What is the asymptotes of f(x)=(x^2+x)/(x-1) ?

The asymptotes of f(x)=(x^2+x)/(x-1) is Vertical: x=1,Slant: y=x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2+x)/(x-1)

asymptotes

f (x) = \frac{x ^{2} + x}{x - 1}

Vertical : x = 1, Slant : y = x + 2

Solution steps

Vertical asymptotes of

\frac{x ^{2} + x}{x - 1} : x = 1

Horizontal Asymptotes of

\frac{x ^{2} + x}{x - 1} :

None

Slant Asymptotes of

\frac{x ^{2} + x}{x - 1} : y = x + 2

Vertical : x = 1, Slant : y = x + 2

f (x) = \frac{x ^{2} - 19 x - 20}{x + 5}

f (x) = \frac{- x ^{3} + x ^{2} + 4}{x ^{2}}

\frac{( 6 x ^{3} + x ^{2} - 15 x )}{6 x ^{2} - 24}

y = \frac{x ^{2} + 1}{x - 1}

f (x) = 2^{x - 2} - 3

What is the asymptotes of f(x)=(x^2+x)/(x-1) ?
The asymptotes of f(x)=(x^2+x)/(x-1) is Vertical: x=1,Slant: y=x+2