What is the asymptotes of f(x)=((2x^2))/(x^2-4) ?

The asymptotes of f(x)=((2x^2))/(x^2-4) is Vertical: x=-2,x=2,Horizontal: y=2

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asymptotes of f(x)=((2x^2))/(x^2-4)

asymptotes

f (x) = \frac{( 2 x ^{2} )}{x ^{2} - 4}

Vertical : x = - 2, x = 2, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2}}{x ^{2} - 4} : x = - 2, x = 2

Horizontal Asymptotes of

\frac{2 x ^{2}}{x ^{2} - 4} : y = 2

Slant Asymptotes of

\frac{2 x ^{2}}{x ^{2} - 4} :

None

Vertical : x = - 2, x = 2, Horizontal : y = 2

f (x) = (3 x - 6 x^{3}) e^{- x}

f (x) = \frac{3 x - 3}{- 2 x + 3}

f (x) = \frac{x ^{2} - 7}{x + 4}

\frac{3 x + 6}{x + 3}

f (x) = ln (6 - ln (x))

What is the asymptotes of f(x)=((2x^2))/(x^2-4) ?
The asymptotes of f(x)=((2x^2))/(x^2-4) is Vertical: x=-2,x=2,Horizontal: y=2