What is the asymptotes of f(x)=(x^2-5)/(x+1) ?

The asymptotes of f(x)=(x^2-5)/(x+1) is Vertical: x=-1,Slant: y=x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2-5)/(x+1)

asymptotes

f (x) = \frac{x ^{2} - 5}{x + 1}

Vertical : x = - 1, Slant : y = x - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 5}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} - 5}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} - 5}{x + 1} : y = x - 1

Vertical : x = - 1, Slant : y = x - 1

f (x) = \frac{x ^{2} + 2 x - 3}{2 x ^{2} - x - 1}

\frac{3 x ^{2} + x - 4}{2 x ^{2} - 5 x}

f (x) = \frac{1}{4 x - 16}

\frac{x ^{2} + 1}{x ^{2} - 4}

\frac{2 ( x ^{2} - 9 )}{x ^{2} - 4}

What is the asymptotes of f(x)=(x^2-5)/(x+1) ?
The asymptotes of f(x)=(x^2-5)/(x+1) is Vertical: x=-1,Slant: y=x-1