What is the asymptotes of f(x)=((5+2^x))/(1-2^x) ?

The asymptotes of f(x)=((5+2^x))/(1-2^x) is Vertical: x=0,Horizontal: y=-1,y=5

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asymptotes of f(x)=((5+2^x))/(1-2^x)

asymptotes

f (x) = \frac{( 5 + 2 ^{x} )}{1 - 2 ^{x}}

Vertical : x = 0, Horizontal : y = - 1, y = 5

Solution steps

Vertical asymptotes of

\frac{5 + 2 ^{x}}{1 - 2 ^{x}} : x = 0

Horizontal Asymptotes of

\frac{5 + 2 ^{x}}{1 - 2 ^{x}} : y = - 1, y = 5

Slant Asymptotes of

\frac{5 + 2 ^{x}}{1 - 2 ^{x}} :

None

Vertical : x = 0, Horizontal : y = - 1, y = 5

f (x) = \frac{4 x + 2}{x + 2}

(x^{2} + 10) (9 - x^{2})

f (x) = \frac{x}{3 + 2 ln ( x )}

\frac{8 x ^{4}}{x ^{4} + 2}

f (x) = lo g_{5} (x + 7)

What is the asymptotes of f(x)=((5+2^x))/(1-2^x) ?
The asymptotes of f(x)=((5+2^x))/(1-2^x) is Vertical: x=0,Horizontal: y=-1,y=5