What is the asymptotes of f(x)=(ln(x+1))/x ?

The asymptotes of f(x)=(ln(x+1))/x is Vertical: x=-1,Horizontal: y=0

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asymptotes of f(x)=(ln(x+1))/x

asymptotes

f (x) = \frac{ln ( x + 1 )}{x}

Vertical : x = - 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{ln ( x + 1 )}{x} : x = - 1

Horizontal Asymptotes of

\frac{ln ( x + 1 )}{x} : y = 0

Slant Asymptotes of

\frac{ln ( x + 1 )}{x} :

None

Vertical : x = - 1, Horizontal : y = 0

f (x) = \frac{4 x}{2 x + 1}

f (x) = \frac{e ^{x}}{x ^{2}}

f (x) = \frac{2 x + 8}{x ^{2} + x - 12}

f (x) = \frac{x ^{2}}{( x ^{2} - 1 )}

f (x) = \frac{2 x - 6}{5 x ^{2} - 16 x + 3}

What is the asymptotes of f(x)=(ln(x+1))/x ?
The asymptotes of f(x)=(ln(x+1))/x is Vertical: x=-1,Horizontal: y=0