What is the asymptotes of f(x)=(2x+8)/(x^2+x-12) ?

The asymptotes of f(x)=(2x+8)/(x^2+x-12) is Vertical: x=3,Horizontal: y=0

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asymptotes of f(x)=(2x+8)/(x^2+x-12)

asymptotes

f (x) = \frac{2 x + 8}{x ^{2} + x - 12}

Vertical : x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{2 x + 8}{x ^{2} + x - 12} : x = 3

Horizontal Asymptotes of

\frac{2 x + 8}{x ^{2} + x - 12} : y = 0

Slant Asymptotes of

\frac{2 x + 8}{x ^{2} + x - 12} :

None

Vertical : x = 3, Horizontal : y = 0

f (x) = \frac{x ^{2}}{( x ^{2} - 1 )}

f (x) = \frac{2 x - 6}{5 x ^{2} - 16 x + 3}

h (x) = \frac{2 x ^{2} + 3}{x - 1}

f (x) = 2^{x + 3} - 1

\frac{x}{x ^{2} + 1}

What is the asymptotes of f(x)=(2x+8)/(x^2+x-12) ?
The asymptotes of f(x)=(2x+8)/(x^2+x-12) is Vertical: x=3,Horizontal: y=0