What is the critical {x^2:x =-2} ?

The critical {x^2:x =-2} is x=-2

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critical {x^2:x<-2,ln(x+5):x>=-2}

critical points

{x^{2} : x < - 2, ln (x + 5) : x \geq - 2}

x = - 2

Solution steps

{x^{2} : x < - 2, ln (x + 5) : x \geq - 2}

Critical Points of

{x^{2} : x < - 2} :

None

Critical Points of

{ln (x + 5) : x \geq - 2} :

None

Combine critical points of all pieces:

None

Evaluate interval endpoint

x = - 2 :

critical point

x = - 2

f (x) = x^{4} + \frac{4}{3} x^{3} - 4 x^{2}

x^{2} + \frac{1}{x ^{2}}

x^{4} - 7 x^{3}

f (x) = x^{4} + y^{4}

f (x) = x^{3} + 6 x^{2} - 8 y + 25 = 13

What is the critical {x^2:x<-2,ln(x+5):x>=-2} ?
The critical {x^2:x<-2,ln(x+5):x>=-2} is x=-2