What is the extreme f(x)=5-6x^2-2x^3 ?

The extreme f(x)=5-6x^2-2x^3 is Minimum(-2,-3),Maximum(0,5)

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extreme f(x)=5-6x^2-2x^3

extreme points

f (x) = 5 - 6 x^{2} - 2 x^{3}

Minimum (- 2, - 3), Maximum (0, 5)

Solution steps

f^{'} (x) = - 6 x^{2} - 12 x

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = - 2

into

5 - 6 x^{2} - 2 x^{3} : - 3

Minimum (- 2, - 3)

Plug

x = 0

into

5 - 6 x^{2} - 2 x^{3} : 5

Maximum (0, 5)

Minimum (- 2, - 3), Maximum (0, 5)

\frac{3}{2} x^{2} + x^{3} + 3 y^{2}

y = u (t - 1) - u (t - 4)

f (x) = x + 3 x [0.4]

f (t) = x

f (x) = 4 x^{3} + 21 x^{2} - 294 x + 9

What is the extreme f(x)=5-6x^2-2x^3 ?
The extreme f(x)=5-6x^2-2x^3 is Minimum(-2,-3),Maximum(0,5)