What is the extreme f(x)=sqrt(x)+\sqrt[3]{x}[0.4] ?

The extreme f(x)=sqrt(x)+\sqrt[3]{x}[0.4] is Minimum(0,0)

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extreme f(x)=sqrt(x)+\sqrt[3]{x}[0.4]

extreme points

f (x) = x + 3 x [0.4]

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{0.5}{x} + \frac{0.13333 \dots}{x ^{\frac{2}{3}}}

Find intervals:

Increasing

: 0 < x < \infty

Plug

x = 0

into

x + 3 x [0.4] : 0

Minimum (0, 0)

f (x, y) = x^{3} + 3 x y + y^{3}

f (t) = x

f (x) = 4 x^{3} + 21 x^{2} - 294 x + 9

f (x) = (4 - x^{2})^{5}

x^{4} - 3 x^{2}

What is the extreme f(x)=sqrt(x)+\sqrt[3]{x}[0.4] ?
The extreme f(x)=sqrt(x)+\sqrt[3]{x}[0.4] is Minimum(0,0)