extreme f(x)=x^2+10+24

Lösung

extrempunkte

f (x) = x^{2} + 10 + 24

Minimum (0, 34)

Schritte zur Lösung

f^{'} (x) = 2 x

Intervalle finden:

Absteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < \infty

Stecke

x = 0

x^{2} + 10 + 24 : 34

Minimum (0, 34)

e x t re m e f (x, y) = ln 4 x^{2} + 18 y^{2} - 36

e x t re m e f (x, y) = x^{2} + 2 x y + 2 y^{2} - 6 x + 10 y + 2

e x t re m e f (x) = \frac{x ^{2}}{1 - x}

e x t re m e f (x) = 4 - x^{2}, - 1 \leq x \leq 2

e x t re m e f (x) = \frac{1}{1 + ∣ x ∣} + \frac{1}{1 + ∣ x - 2 ∣}