What is the extreme f(x)=x^3-6x^2-15x ?

The extreme f(x)=x^3-6x^2-15x is Maximum(-1,8),Minimum(5,-100)

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extreme f(x)=x^3-6x^2-15x

extreme points

f (x) = x^{3} - 6 x^{2} - 15 x

Maximum (- 1, 8), Minimum (5, - 100)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x - 15

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 1

into

x^{3} - 6 x^{2} - 15 x : 8

Maximum (- 1, 8)

Plug

x = 5

into

x^{3} - 6 x^{2} - 15 x : - 100

Minimum (5, - 100)

Maximum (- 1, 8), Minimum (5, - 100)

f (x) = \frac{( x ^{2} - 3 )}{x - 2}

f (x) = 4 x + \frac{9}{x}

f (x) = x^{3} + 3 x^{2} + 3 x

f (x) = \frac{1}{4} x^{4} - x^{3} - 4 x + 2

120 x - 2 x^{2} - x y - 3 y^{2} + 160 y + 7

What is the extreme f(x)=x^3-6x^2-15x ?
The extreme f(x)=x^3-6x^2-15x is Maximum(-1,8),Minimum(5,-100)