What is the extreme f(x)=x^3-4x^2-11x+30 ?

The extreme f(x)=x^3-4x^2-11x+30 is Maximum(-1,36),Minimum(11/3 ,-400/27)

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extreme f(x)=x^3-4x^2-11x+30

extreme points

f (x) = x^{3} - 4 x^{2} - 11 x + 30

Maximum (- 1, 36), Minimum (\frac{11}{3}, - \frac{400}{27})

Solution steps

f^{'} (x) = 3 x^{2} - 8 x - 11

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < \frac{11}{3},

Increasing

: \frac{11}{3} < x < \infty

Plug

x = - 1

into

x^{3} - 4 x^{2} - 11 x + 30 : 36

Maximum (- 1, 36)

Plug

x = \frac{11}{3}

into

x^{3} - 4 x^{2} - 11 x + 30 : - \frac{400}{27}

Minimum (\frac{11}{3}, - \frac{400}{27})

Maximum (- 1, 36), Minimum (\frac{11}{3}, - \frac{400}{27})

f (x) = x^{2} - 8 x + 16

f (x) = \frac{1}{16 - x ^{2} - y ^{2}}

f (x) = - 3 x^{2} + 6 x

f (x, y) = x^{2} + (y - 2)^{2}

f (x, y) = - 4 y^{2} - 5 x^{3} + 13 x^{2}

What is the extreme f(x)=x^3-4x^2-11x+30 ?
The extreme f(x)=x^3-4x^2-11x+30 is Maximum(-1,36),Minimum(11/3 ,-400/27)