What is the extreme f(x)=x^3+6x^2-15x+2 ?

The extreme f(x)=x^3+6x^2-15x+2 is Maximum(-5,102),Minimum(1,-6)

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extreme f(x)=x^3+6x^2-15x+2

extreme points

f (x) = x^{3} + 6 x^{2} - 15 x + 2

Maximum (- 5, 102), Minimum (1, - 6)

Solution steps

f^{'} (x) = 3 x^{2} + 12 x - 15

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 5

into

x^{3} + 6 x^{2} - 15 x + 2 : 102

Maximum (- 5, 102)

Plug

x = 1

into

x^{3} + 6 x^{2} - 15 x + 2 : - 6

Minimum (1, - 6)

Maximum (- 5, 102), Minimum (1, - 6)

x^{3} + y^{3} - 6 x y

f (x) = \frac{2 x ^{2}}{x + 1}

f (x) = 5 - x^{2}

f (x) = x - x

f (x) = (\frac{ln ( x )}{x ^{2}})

What is the extreme f(x)=x^3+6x^2-15x+2 ?
The extreme f(x)=x^3+6x^2-15x+2 is Maximum(-5,102),Minimum(1,-6)