en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=\sqrt[3]{x+4}

Solution

extreme points

Solution

None

Solution steps

f^{'} (x) = \frac{1}{3 ( x + 4 ) ^{\frac{2}{3}}}

Find intervals:

Increasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

None

Popular Examples

extreme f(x)=-5x^4+15x^3-17 extreme points

f (x) = - 5 x^{4} + 15 x^{3} - 17

extreme f(x)=x^3+y^3+2x^2+4y^2+6 extreme points

f (x) = x^{3} + y^{3} + 2 x^{2} + 4 y^{2} + 6

extreme f(x)=(e^x)/(x-1)extreme points

f (x) = \frac{e ^{x}}{x - 1}

extreme f(x)=1296x-0.12x^3 extreme points

f (x) = 1296 x - 0.12 x^{3}

extreme f(x)=ln(x^2+3x+7)extreme points

f (x) = ln (x^{2} + 3 x + 7)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=\sqrt[3]{x+4} ?
The extreme f(x)=\sqrt[3]{x+4} is None