extreme f(x)=x^2+6x+6

Lösung

extrempunkte

f (x) = x^{2} + 6 x + 6

Minimum (- 3, - 3)

Schritte zur Lösung

f^{'} (x) = 2 x + 6

Intervalle finden:

Absteigend

: - \infty < x < - 3,

Ansteigend

: - 3 < x < \infty

Stecke

x = - 3

x^{2} + 6 x + 6 : - 3

Minimum (- 3, - 3)

e x t re m e f (x, y) = 2 x^{3} - 3 x^{2} y - 12 x^{2} - 3 y^{2}

e x t re m e f (x, y) = e^{x - y} (x^{2} - 2 y^{2})

e x t re m e \frac{x ^{3}}{x + 1}

e x t re m e f (x) = x^{3} + 3 \cdot x^{2} - 9 x + 27

e x t re m e f (x) = \frac{x ^{3}}{3} - 4 x^{2} + 7 x + 8