What is the extreme f(x,y)=6x-4y-x^2-2y^2 ?

The extreme f(x,y)=6x-4y-x^2-2y^2 is Maximum(3,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=6x-4y-x^2-2y^2

extreme points

f (x, y) = 6 x - 4 y - x^{2} - 2 y^{2}

Maximum (3, - 1)

Solution steps

Find the critical points:

(3, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 4

D (x, y) = 8

Check the sign of at each critical point

Check critical point

(3, - 1) :

Maximum

Maximum (3, - 1)

f (x) = 3 x ln (x)

f (x, y) = 5 x^{2} + 5 y^{2} + 5 x y - 10 x - 5 y + 18

f (x, y) = x^{3} + 3 x y^{2} - 15 x^{2} - 15 y^{2} + 72 x

f (x, y) = 10 - 4 x - 5 y

f (x, y) = x^{2} - \frac{1}{2} y^{2} + 3 x

What is the extreme f(x,y)=6x-4y-x^2-2y^2 ?
The extreme f(x,y)=6x-4y-x^2-2y^2 is Maximum(3,-1)