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Popular >

extreme f(x)=ln(5-2x^2)

Solution

extreme points

f (x) = ln (5 - 2 x^{2})

Solution

Maximum (0, ln (5))

Solution steps

f^{'} (x) = - \frac{4 x}{5 - 2 x ^{2}}

Find intervals:

Increasing

: - \frac{5}{2} < x < 0,

Decreasing

: 0 < x < \frac{5}{2}

Plug

x = 0

into

ln (5 - 2 x^{2}) : ln (5)

Maximum (0, ln (5))

Popular Examples

extreme f(x)=2x^3-11/2 x^2-10x+2 extreme points

f (x) = 2 x^{3} - \frac{11}{2} x^{2} - 10 x + 2

extreme f(x,y)=8y^2+5x^2-10y+6x-10 extreme points

f (x, y) = 8 y^{2} + 5 x^{2} - 10 y + 6 x - 10

extreme f(x)=8x^5-120x^3+43 extreme points

f (x) = 8 x^{5} - 120 x^{3} + 43

extreme f(x)=(x^2)/(x^4+1)extreme points

f (x) = \frac{x ^{2}}{x ^{4} + 1}

extreme f(x)=(8x)^3-(5x)^2-3x extreme points

f (x) = (8 x)^{3} - (5 x)^{2} - 3 x

Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(5-2x^2) ?
The extreme f(x)=ln(5-2x^2) is Maximum(0,ln(5))