What is the extreme f(x)=2x^3-9x^2+2 ?

The extreme f(x)=2x^3-9x^2+2 is Maximum(0,2),Minimum(3,-25)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^3-9x^2+2

extreme points

f (x) = 2 x^{3} - 9 x^{2} + 2

Maximum (0, 2), Minimum (3, - 25)

Solution steps

f^{'} (x) = 6 x^{2} - 18 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 0

into

2 x^{3} - 9 x^{2} + 2 : 2

Maximum (0, 2)

Plug

x = 3

into

2 x^{3} - 9 x^{2} + 2 : - 25

Minimum (3, - 25)

Maximum (0, 2), Minimum (3, - 25)

f (x) = 4 x^{3} - x^{2} - 14 x - 42

f (x) = - cos (x) - sin (x)

f (x) = 8 x - x^{2}

f (x) = ln (x + 2) (x - 1)^{2}

2 x^{3} - 3 x^{2} - 12 x

What is the extreme f(x)=2x^3-9x^2+2 ?
The extreme f(x)=2x^3-9x^2+2 is Maximum(0,2),Minimum(3,-25)