What is the extreme f(x)=2sqrt(x)-x ?

The extreme f(x)=2sqrt(x)-x is Maximum(0,0),Minimum(1,1)

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extreme f(x)=2sqrt(x)-x

extreme points

f (x) = 2 x - x

Maximum (0, 0), Minimum (1, 1)

Solution steps

f^{'} (x) = \frac{1}{x} - 1

Find intervals:

Decreasing

: 0 \leq x < 1,

Increasing

: 1 < x < \infty

Plug

x = 0

into

2 x - x : 0

Maximum (0, 0)

Plug

x = 1

into

2 x - x : 1

Minimum (1, 1)

Maximum (0, 0), Minimum (1, 1)

f (x) = 3 x^{2} - 12 x + 15

f (x, y) = 4 x^{2} - 3 x y + y^{2}

f (x) = x^{4} - 6 x^{3}

f (x) = x^{5} - 2 x^{3} + x + x y^{2}

f (x) = x^{4} + 4 x^{3} - 2 x^{2} - 12 x

What is the extreme f(x)=2sqrt(x)-x ?
The extreme f(x)=2sqrt(x)-x is Maximum(0,0),Minimum(1,1)