What is the domain of f(x)=x^2+2x-3,-4<= x<= 4 ?

The domain of f(x)=x^2+2x-3,-4<= x<= 4 is -4<= x<= 4

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domain of f(x)=x^2+2x-3,-4<= x<= 4

domain

f (x) = x^{2} + 2 x - 3, - 4 \leq x \leq 4

- 4 \leq x \leq 4

Interval Notation

[- 4, 4]

Solution steps

Set the domain to the given interval

- 4 \leq x \leq 4

The function has no undefined points nor domain constraints. Therefore, the domain is

- 4 \leq x \leq 4

f (x) = 7 - 4 x

- x^{2} + 2 x + 1

f (x) = \frac{x + 4}{x + 5}

f (x) = \frac{x + 1}{x - 5}

sin (\frac{1}{x})

What is the domain of f(x)=x^2+2x-3,-4<= x<= 4 ?
The domain of f(x)=x^2+2x-3,-4<= x<= 4 is -4<= x<= 4