What is the domain of f(x)= 3/4 sqrt(x+2-3) ?

The domain of f(x)= 3/4 sqrt(x+2-3) is x>= 1

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domain of f(x)= 3/4 sqrt(x+2-3)

domain

f (x) = \frac{3}{4} x + 2 - 3

x \geq 1

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

\frac{x ^{2} - 3}{ln ( x ^{2} - 3 )}

f (x) = - cos (x)

3 \cdot e^{- 5 x}

f (x) = \frac{x ^{2}}{x + 1}

\frac{1}{1 - e ^{x}}

What is the domain of f(x)= 3/4 sqrt(x+2-3) ?
The domain of f(x)= 3/4 sqrt(x+2-3) is x>= 1